Lab 11 · Fluid Mechanics · Archimedes' Principle

Archimedes' Principle

Measure the buoyant force on submerged objects, verify that it equals the weight of displaced fluid, and calculate the density of several metal samples using two independent methods.

Theory — Buoyancy and Archimedes' Principle

Density

Density is defined as mass per unit volume. It assumes a solid material with no internal voids — any air pockets would change the volume without changing the mass, giving an inaccurate density reading.

Density ρ = m / V     [kg/m³ or g/cm³]

Conversion:   1 g/cm³ = 1000 kg/m³

Archimedes' Principle

When an object is submerged in a fluid, the fluid exerts an upward buoyant force equal to the weight of the fluid displaced by the object. This principle applies to all fluids — liquids and gases alike.

Archimedes' Principle F_buoyant = Weight of fluid displaced
F_b = ρ_fluid · V_displaced · g

For water (ρ = 1000 kg/m³ = 1 g/cm³):
F_b = m_displaced_water · g
F_b = W_object_in_air − W_object_in_water

Section I — Displaced Water Method

Submerge an object in an overflow beaker. Collect and weigh the displaced water. The buoyant force equals the weight of this water. Also measure its volume in a graduated cylinder — confirms that 1 mL = 1 cm³ of water has mass 1 gram.

Section II — Weight in Water Method

Weigh the object in air, then weigh it while fully submerged. The difference in apparent weight IS the buoyant force. This gives a second independent measurement of F_b to compare with Section I.

Calculating Object Density

Once we know the buoyant force and the density of water, we can find the object's density without directly measuring its volume:

Density from Buoyancy V_object = V_displaced = m_displaced_water / ρ_water

ρ_object = m_object / V_object

Combined:
ρ_object = (W_air / F_buoyant) × ρ_water

Percent Error

Percent Error vs Reference Value
% error = |experimental − reference| / reference × 100%

Instructions — Running the Virtual Experiment

Section I — Mass and Volume of Displaced Water

1
Select an object from the dropdown menu in the Section I simulation panel. Each object represents a different metal sample.
2
Click Submerge Object. The object sinks into the overflow beaker and water flows into the collection beaker. The simulation shows the water level rising.
3
Record the mass of displaced water shown on the balance in grams. Also record the volume shown in the graduated cylinder (mL). Verify that mass (g) ≈ volume (mL) for water.
4
Calculate the buoyant force using F_b = m_water × g (convert grams to kg first). Record in your data table.
5
Repeat for each metal sample. Reset between objects using the Reset button.

Section II — Weight in Air and Water

1
Select the same object in the Section II panel. The scale shows the object suspended in air. Record the mass in grams as "Mass in Air."
2
Click Submerge. The water beaker rises until the object is fully submerged. Record the new scale reading as "Mass in Water."
3
Calculate the buoyant force: F_b = (Mass in Air − Mass in Water) × g. Compare this to your Section I result — they should agree closely.
4
Calculate the density of each object using ρ = (W_air / F_b) × ρ_water. Record in your data table.
5
Look up reference densities and calculate percent error for each metal. Record everything in the data table and answer the team questions.

Simulation — Buoyancy Experiment

Archimedes' Principle Virtual Lab | Select object and section to begin
Mass of Water
grams
Volume of Water
mL
Buoyant Force
N
Object Volume
cm³
Mass in Air
grams
Mass in Water
grams
Buoyant Force
N
Calculated Density
g/cm³

Data Table — All Samples

Sample Mass in Air (g) Mass in Water (g) F_b (N) Volume (cm³) Density (g/cm³) Reference (g/cm³) % Error
Brass Sample 18.50
Brass Sample 28.50
Aluminum2.70
Iron/Steel7.87
Copper8.96

Team Questions

Question 1. If the density of a substance is 12 g/cm³, what is its density in kg/m³? Show your conversion.
Question 2. The density of water is 1 g/cm³. When an object is submerged in water and displaces 10 cm³, what is the buoyant force in Newtons? (Remember: buoyant force = weight of fluid displaced.)
Question 3. From your data table, record the density of one brass sample in g/cm³ and convert it to kg/m³. How does your experimental value compare to the reference value of 8.50 g/cm³?
Question 4. Calculate the percent error between your experimentally determined brass density and the reference value (8.50 g/cm³). Round to two significant digits.

Example Lab Report

Sample report demonstrating the expected format and level of detail. Use as a guide for your own submission.

Lab 11 — Archimedes' Principle

Physics 171 | Section: [Your Section] | Date: [Date]

Lab Members: [Names of all members present]

Introduction

This lab tests Archimedes' principle — that the buoyant force on a submerged object equals the weight of fluid displaced. We measure buoyancy using two independent methods: (1) collecting and weighing displaced water, and (2) comparing apparent weight in air versus water. We also determine the density of metal samples and compare to reference values.

Background — Key Equations

Density: ρ = m/V. For water: ρ_water = 1.00 g/cm³ = 1000 kg/m³.

Buoyant force: F_b = ρ_fluid · V_displaced · g = (W_air − W_water)

Object density: ρ_object = (W_air / F_b) · ρ_water

Percent error: |experimental − reference| / reference × 100%

Section I Results — Displaced Water

SampleMass of Displaced Water (g)Volume (mL)F_b (N)
Brass Sample 18.428.40.0826
Brass Sample 26.186.20.0606
Aluminum9.259.30.0907
Iron/Steel7.637.60.0748
Copper5.575.60.0546

Note: Mass (g) ≈ Volume (mL) for water, confirming ρ_water = 1.00 g/cm³. Small differences due to reading precision.

Section II Results — Weight in Air and Water

SampleMass Air (g)Mass Water (g)F_b (N)Density (g/cm³)Reference (g/cm³)% Error
Brass Sample 171.5763.150.08268.518.500.12%
Brass Sample 252.5346.350.06068.498.500.12%
Aluminum24.9815.730.09072.702.700.00%
Iron/Steel60.0252.390.07487.877.870.00%
Copper49.9344.360.05468.958.960.11%

Sample Calculation — Brass Sample 1

F_b from Section I: F_b = 0.00842 kg × 9.81 m/s² = 0.0826 N

F_b from Section II: F_b = (71.57 − 63.15) g × 0.001 kg/g × 9.81 = 0.0826 N ✓

Object Volume: V = m_water/ρ_water = 8.42 g / 1.00 g/cm³ = 8.42 cm³

Object Density: ρ = 71.57 g / 8.42 cm³ = 8.50 g/cm³

Convert to kg/m³: 8.50 g/cm³ × 1000 = 8500 kg/m³

% Error: |8.51 − 8.50| / 8.50 × 100% = 0.12%

Team Question Answers

Q1: 12 g/cm³ × 1000 = 12,000 kg/m³ (since 1 g/cm³ = 1000 kg/m³)

Q2: Volume displaced = 10 cm³ = 10 × 10⁻⁶ m³. Mass of water = 10 g = 0.010 kg. F_b = 0.010 × 9.81 = 0.0981 N ≈ 0.098 N

Q3: Brass Sample 1 density = 8.51 g/cm³ = 8510 kg/m³. This is within 0.12% of the reference value of 8500 kg/m³.

Q4: % error = |8.51 − 8.50| / 8.50 × 100% = 0.12% (two significant digits)

Discussion

Both measurement methods (displaced water and apparent weight loss) gave identical buoyant force values to three significant figures, strongly confirming Archimedes' principle. The experimental densities agreed with reference values to within 0.12% for all samples. Minor discrepancies are attributed to small amounts of water remaining in the overflow tube between runs and parallax errors in reading the graduated cylinder meniscus.

The plastic cylinder floated rather than sinking — this confirmed that objects with density less than water (ρ_plastic ≈ 0.90 g/cm³ < 1.00 g/cm³) experience a buoyant force greater than their weight, causing them to float until equilibrium is reached at the surface.

Conclusion

The experiment successfully verified Archimedes' principle. The buoyant force measured by two independent methods agreed within experimental uncertainty. Experimental densities for all metal samples matched reference values to within 0.2%, demonstrating that the buoyancy method is an accurate technique for density determination without direct volume measurement.

Practice Questions

Show all work and include units in your answers.

Question 1
A metal block weighs 58.0 N in air and 43.5 N when fully submerged in water. What is the buoyant force? What volume of water is displaced? What is the density of the metal?
Hint: F_b = W_air − W_water. V_displaced = F_b / (ρ_water × g). ρ_metal = W_air / (F_b × g⁻¹ × ρ_water⁻¹).
Question 2
A piece of aluminum (ρ = 2700 kg/m³) has a volume of 25.0 cm³. What is its weight in air? What is the buoyant force when fully submerged in water? What does it appear to weigh in water?
Hint: m = ρ·V. W = mg. F_b = ρ_water·V·g. Apparent weight = W − F_b.
Question 3
A canoe and its contents weigh 1800 N. What volume of water does it displace when floating in equilibrium? If the canoe hull has a total volume of 0.350 m³, how much of this volume is submerged?
Hint: For floating equilibrium, F_b = W. V_displaced = W / (ρ_water × g).
Question 4
An unknown metal has a mass of 85.6 g in air and appears to have a mass of 75.4 g when submerged in water. Identify the metal by calculating its density and comparing to: iron (7.87 g/cm³), brass (8.50 g/cm³), copper (8.96 g/cm³), lead (11.3 g/cm³).
Hint: ρ = m_air / (m_air − m_water) × ρ_water. This is the direct density formula from buoyancy.
Question 5
A balloon is filled with helium (ρ = 0.164 kg/m³) and has a total volume of 0.0150 m³. The balloon material has a mass of 2.00 g. What is the net upward force on the balloon in air (ρ_air = 1.29 kg/m³)?
Hint: Net force = F_buoyant − W_helium − W_balloon. F_b = ρ_air·V·g.
Question 6 — Challenge
A geologist finds a rock sample with a mass of 142 g. When submerged in water it displaces 52.0 mL. Calculate the density and identify whether the rock could be granite (2.65 g/cm³), basalt (3.01 g/cm³), or magnetite (5.15 g/cm³). Also calculate the percent error from your best match.
Hint: V = 52.0 cm³ (since 1 mL = 1 cm³). ρ = m/V. Then compare to reference values.