Theory — Reaction Types, Balancing, and Yield

Types of Chemical Reaction

Most reactions fall into a few recognisable patterns. Identifying the type often helps you predict the products and balance the equation.

TypePatternExample
Synthesis (combination)A + B → ABN₂ + 3H₂ → 2NH₃
DecompositionAB → A + B2KClO₃ → 2KCl + 3O₂
Single replacementA + BC → AC + B2K + MgBr₂ → 2KBr + Mg
Double replacementAB + CD → AD + CBFeCl₃ + 3NaOH → Fe(OH)₃ + 3NaCl
Combustionfuel + O₂ → CO₂ + H₂OCH₄ + 2O₂ → CO₂ + 2H₂O
Neutralisationacid + base → salt + waterHCl + NaOH → NaCl + H₂O

Balancing Equations

A balanced equation has the same number of each atom on both sides — mass is conserved. Balance using coefficients only; never change subscripts. Treat polyatomic ions (such as NO₃⁻ and SO₄²⁻) as units where possible, and remember the diatomic elements H₂, O₂, N₂, F₂, Cl₂, Br₂, I₂.

Example — Balancing skeleton:  __ C₃H₈ + __ O₂ → __ CO₂ + __ H₂O
balanced:  C₃H₈ + 5 O₂ → 3 CO₂ + 4 H₂O

C: 3 = 3 · H: 8 = 8 · O: 10 = 10
Adjust coefficients only until every element matches

Theoretical and Percent Yield

The theoretical yield is the maximum product predicted by the balanced equation from the amounts of reactant used. The percent yield compares what was actually obtained to that maximum.

Yield moles of reactant = mass ÷ molar mass
moles of product = moles of reactant × (mole ratio from equation)
theoretical yield = moles of product × molar mass of product
percent yield = (actual yield ÷ theoretical yield) × 100 %
Percent yield is normally less than 100 % in a real experiment

Conservation of Mass

Atoms are not created or destroyed; coefficients make both sides equal.

Empirical vs Molecular

Empirical formula is the simplest whole-number ratio; the molecular formula is a whole-number multiple of it.

Percent Yield

Actual ÷ theoretical × 100. A real reaction usually gives less than 100 %.

Apparatus

The equipment a real equation-balancing experiment uses. In the simulation these are modelled for you, but the readings correspond to what each instrument would measure.

builds molecules
Molecular model kit
Shows atoms are conserved, so equations must balance.
0.000 gmeasures mass
Analytical balance
Demonstrates conservation of mass in a reaction.
reagent solutions
Reagent bottles
Hold the reactant solutions for the demonstrations.
reaction flask
Reaction flask
Where the reactants combine to form products.
element reference
Periodic table chart
Gives the formulas and charges needed to write equations.
holds solutions
Beaker
Mixes and observes the reacting solutions.

Instructions — Running the Virtual Experiment

The simulation has three sections. Complete each one and record your results, with screenshots, in your lab report.

Part 1 — Reaction Types (Reaction Types tab)
1
Open Simulation → Reaction Types. For each reaction shown, choose the type (synthesis, decomposition, single replacement, double replacement, or combustion) and check your answer.
2
Record at least five reactions with their correct types in your report.
Part 2 — Balancing (Balancing tab)
1
Open Balancing. For each skeleton equation, type whole-number coefficients. The atom tally shows the count of each element on both sides.
2
Adjust coefficients until every element matches in the lowest whole-number ratio, then click Check. Record at least three balanced equations with a screenshot.
Part 3 — Percent Yield (Yield tab)
1
Open Yield. Select a reaction and one of its three reactant sets (each set uses amounts that react together completely). Predict the mass of product, then click Calculate yield to see the theoretical yield.
2
Enter the actual yield obtained and record the reactant amounts, theoretical yield, actual yield, and percent yield for at least two cases.
Part 4 — Empirical & Molecular Formulae (Empirical & Molecular tab)
1
Open Empirical & Molecular. In Part A, choose a percent composition and work out the mole ratio yourself, then click Find empirical formula to check. Record the moles of each element, the simplest whole-number ratio, and the empirical formula.
2
In Part B, enter the molar mass and click Find molecular formula. Record n = molar mass ÷ empirical-formula mass and the resulting molecular formula for at least two compounds.

Simulation — Balancing Chemical Reactions

Balancing Virtual LabRecognise · Balance · Yield
N₂ + 3 H₂ → 2 NH₃

Reaction

Reaction 1 of 10

Score
Correct0
Attempted0
Choose the pattern that matches the reactants and products.
Left side (reactants)
Right side (products)

Choose an equation

How to balance
Rulecoefficients only
GoalL = R per atom
Diatomic: H₂ O₂ N₂ F₂ Cl₂ Br₂. Keep polyatomic ions together.
Actual vs theoretical yield— %
N₂ + 3 H₂ → 2 NH₃

Choose a reaction and one of its three reactant sets. Each set uses amounts that react together completely. Predict the yield yourself first, then click Calculate yield to check.

Reaction

Reactant amounts

Reactant amounts
N₂14.01 g
H₂3.02 g
Predict the product mass, then click Calculate yield.
Enter a percent composition, then find the empirical formula

Part A — Empirical formula

Part B — Molecular formula

Uses the empirical formula from Part A. n = molar mass ÷ empirical-formula mass.

Result
Empirical formula
Empirical mass— g/mol
n = M ÷ emp. mass
Molecular formula
Find the empirical formula first, then the molecular formula.

Team Questions

Question 1. What type of reaction is 2KClO₃ → 2KCl + 3O₂? (synthesis, decomposition, single replacement, double replacement, or combustion)
Question 2. Balance: __ H₂ + __ O₂ → __ H₂O. Type the three coefficients (e.g. 2,1,2).
Question 3. Balance: __ C₃H₈ + __ O₂ → __ CO₂ + __ H₂O. Type the four coefficients (e.g. 1,5,3,4).
Question 4. What type of reaction is CH₄ + 2O₂ → CO₂ + 2H₂O? (Type the type)
Question 5. A reaction has a theoretical yield of 17.0 g and an actual yield of 14.5 g. What is the percent yield? (Type to 1 decimal, e.g. 85.3)
Question 6. A compound has empirical formula CH₂O and a molar mass of 180 g/mol. The empirical formula mass is 30 g/mol. What is the molecular formula? (Type it, e.g. C6H12O6)
Question 7 — Challenge. When balancing, are you allowed to change a subscript to make the atoms balance? (yes or no)

Example Lab Report

Sample report demonstrating the expected format. Include labelled screenshots of each section, and your balanced equations for every reaction you completed.

Balancing Chemical Reactions

Chemistry | Section: [Your Section] | Date: [Date]

Lab Members: [Names of all members present]

Purpose

To recognise the major types of chemical reaction, to balance chemical equations by conservation of mass, and to calculate the theoretical and percent yield of a reaction.

Method

Using the virtual lab, reactions were first classified by type, then balanced by adjusting coefficients until the atom tally matched on both sides, and finally analysed for yield by choosing a reactant set and comparing the actual yield with the theoretical yield. Screenshots were taken of each section.

Results

Reaction types (examples):

N₂ + 3H₂ → 2NH₃ — synthesis
2KClO₃ → 2KCl + 3O₂ — decomposition
2K + MgBr₂ → 2KBr + Mg — single replacement
FeCl₃ + 3NaOH → Fe(OH)₃ + 3NaCl — double replacement
CH₄ + 2O₂ → CO₂ + 2H₂O — combustion

Balanced equations (examples):

2H₂ + O₂ → 2H₂O
C₃H₈ + 5O₂ → 3CO₂ + 4H₂O
4P + 5O₂ → 2P₂O₅

Yield (worked example): for N₂ + 3H₂ → 2NH₃, Set A (14.01 g N₂ with 3.02 g H₂, which react together completely):

mol N₂ = 14.01 / 28.02 = 0.500 mol
mol NH₃ = 2 × 0.500 = 1.00 mol
theoretical = 1.00 × 17.03 = 17.03 g
actual = 14.5 g → percent yield = 14.5 / 17.03 × 100 = 85.1 %

Conclusion

Reactions were correctly classified into synthesis, decomposition, single and double replacement, and combustion. All equations were balanced by conservation of mass using coefficients only. The percent yield of ammonia was 85.2 %, less than 100 % as expected for a real process where some product is lost or the reaction does not go to completion.

Practice Questions

Show all work. Balance with coefficients only; remember the diatomic elements and keep polyatomic ions together.

Question 1
Balance and classify: KClO₃ → KCl + O₂.
Hint: 2KClO₃ → 2KCl + 3O₂; decomposition.
Question 2
Balance and classify: Al + Cl₂ → AlCl₃.
Hint: 2Al + 3Cl₂ → 2AlCl₃; synthesis.
Question 3
Balance the double-replacement reaction: AgNO₃ + MgCl₂ → AgCl + Mg(NO₃)₂.
Hint: 2AgNO₃ + MgCl₂ → 2AgCl + Mg(NO₃)₂.
Question 4
For 2H₂ + O₂ → 2H₂O, a set uses 4.03 g of H₂ with 32.0 g of O₂ (which react together completely). What is the theoretical yield of water?
Hint: mol O₂ = 32.0/32.00 = 1.00; mol H₂O = 2.00; mass = 2.00 × 18.02 = 36.04 g.
Question 5
A compound has empirical formula CH₂O (empirical mass 30 g/mol) and molar mass 180 g/mol. Find the molecular formula.
Hint: 180/30 = 6, so multiply the empirical formula by 6.
Question 6 — Challenge
Octane burns as 2C₈H₁₈ + 25O₂ → 16CO₂ + 18H₂O. Explain why the coefficient on O₂ is so large, and identify the reaction type.
Hint: count the O atoms needed by the products; combustion.