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Mechanics · Energy Conservation

Conservation of Energy

Send a skater down a track and watch gravitational potential energy turn into kinetic energy and back again. On a frictionless track the total mechanical energy stays constant; switch on friction and watch some of it drain away into thermal energy. Measure height and speed, calculate KE, PEg, and ME, and verify the Law of Conservation of Energy.

Theory — Conservation of Mechanical Energy

Two Forms of Mechanical Energy

A moving object on a track has two kinds of mechanical energy: kinetic energy (energy of motion) and gravitational potential energy (stored energy of height). As the skater rolls up and down the track, energy continuously converts between these two forms.

Kinetic and Potential Energy KE = ½ m v²  (energy of motion)
PEg = m g h  (energy of height)

m = mass (kg), v = speed (m/s), g = 9.8 m/s², h = height (m)

The Law of Conservation of Energy

Energy cannot be created or destroyed — only transformed. The total mechanical energy is the sum of kinetic and potential energy. On a frictionless track, with only gravity acting, mechanical energy is conserved: it has the same value at every point.

Total Mechanical Energy E_mech = KE + PEg

Frictionless: E_mech is the same at every point on the track
As h falls, KE rises by exactly the amount PEg falls

Non-Conservative Forces — Friction

When friction acts, the mechanical energy is not conserved: some of it is converted into thermal energy (heat). The skater does not return to its original height. But the total energy — mechanical plus thermal — is still conserved, in keeping with the first law of thermodynamics.

With Friction E_mech,initial = E_mech,final + E_thermal

% Loss = (E_mech,initial − E_mech,final) / E_mech,initial × 100
Lost mechanical energy becomes heat — total energy is still conserved

At the top

Speed is zero, so KE = 0 and all the energy is potential (PEg maximum).

At the bottom

Height is zero, so PEg = 0 and all the energy is kinetic (KE maximum, fastest point).

With friction

Each pass loses mechanical energy to heat, so the skater rises a little less each time.

QuantityFormulaNotes
Kinetic energyKE = ½mv²maximum at the bottom
Potential energyPEg = mghmaximum at the top
Mechanical energyE_mech = KE + PEgconstant if frictionless
With frictionE_mech,i = E_mech,f + E_thermalmechanical energy drops

Instructions — Running the Virtual Experiment

The Frictionless Track tab lets you verify that mechanical energy is conserved by reading KE, PEg, and ME at any point; the Friction Track tab shows mechanical energy draining into thermal energy. Record every reading in your lab report with screenshots of the bar graph and pie chart.

Parts 1 & 2 — Frictionless (Frictionless Track tab)
1
Open Simulation → Frictionless Track. The PEg = 0 reference is at the bottom. Set the mass and the start height to 6.0 m, then release the skater. Watch the bar graph and pie chart swap KE and PEg.
2
Pause and read height h and speed v at three points: P₁ (start, v = 0), P₂ (the very bottom, h = 0), and P₃ (an intermediate height such as 3.0 m). Record each.
3
For each point compute PEg = mgh, KE = ½mv², and E_mech = KE + PEg. Confirm E_mech is the same at all three points.
Part 3 — Friction (Friction Track tab)
1
Open Friction Track. Set the mass to large and friction to "lots," start the skater at 6.0 m, and record E_mech at the start (v = 0).
2
Let the skater complete one full pass to the peak on the opposite side, pause, and record the new E_mech and the thermal energy. Compute the % loss = (E_mech,i − E_mech,f)/E_mech,i × 100.

Simulation — Energy Skate Track

Conservation of Energy Virtual LabRelease the skater and watch the energy convert
kinetic energy
potential energy
PEg = 0 reference at the bottom · g = 9.8 m/s².

Skater & track

Energy readout
Height h6.00 m
Speed v0.00 m/s
PEg = mgh1176 J
KE = ½mv²0 J
E_mech = KE+PEg1176 J
All energy is potential at the top.
Pointh (m)v (m/s)PEg (J)KE (J)E_mech (J)
Release the skater, pause, and click "Record this point" at P₁, P₂, P₃.
KE
PEg
thermal
Friction converts mechanical energy to heat.

Friction track

Energy readout
Height h6.00 m
Speed v0.00 m/s
KE0 J
PEg3528 J
Thermal0 J
E_mech = KE+PEg3528 J
Release and let the skater complete one pass.

Team Questions

Question 1. A 20 kg skater starts at rest at a height of 6.0 m. Using PEg = mgh with g = 9.8, find the potential energy at the start. (Type just the number in J — e.g. 1176)
Question 2. On a frictionless track, what is the total mechanical energy of that skater at the very bottom (h = 0)? (Type just the number in J)
Question 3. At the bottom all the energy is kinetic. Using KE = ½mv² = 1176 J with m = 20 kg, find the skater's speed. (Type just the number in m/s — e.g. 10.8)
Question 4. At a height of 3.0 m (half the start height) on the frictionless track, how is the energy split? (Answer: "half KE half PE", "all KE", or "all PE")
Question 5. With friction, a skater starts with 1176 J of mechanical energy and has 784 J after one pass. How much energy became thermal? (Type just the number in J)
Question 6. For that friction case, what percentage of the mechanical energy was lost? Use (1176−784)/1176×100. (Type just the number — e.g. 33.3)
Question 7 — Challenge. Where the mechanical energy "disappears" with friction, where does it actually go? (One word)

Example Lab Report

Sample report demonstrating the expected format and level of detail. Use as a guide for your own submission, and include labelled screenshots of the bar graph and pie chart at each point.

Conservation of Energy

Physics | Section: [Your Section] | Date: [Date]

Lab Members: [Names of all members present]

Purpose

To verify the Law of Conservation of Mechanical Energy using a virtual skate track. In the frictionless case, the total mechanical energy (KE + PEg) is measured at three points and shown to be constant. In the friction case, the mechanical energy lost in one pass is measured and shown to equal the thermal energy generated.

Theory

Mechanical energy is E_mech = KE + PEg, with KE = ½mv² and PEg = mgh. With only gravity acting (no friction), E_mech is conserved. When friction acts, mechanical energy is converted to thermal energy, so E_mech,initial = E_mech,final + E_thermal and the percentage lost is (E_mech,i − E_mech,f)/E_mech,i × 100.

KE = ½mv² · PEg = mgh · E_mech = KE + PEg
Friction: E_mech,i = E_mech,f + E_thermal (g = 9.8 m/s²)

Part 2 — Frictionless (m = 20 kg, h_start = 6.0 m)

Pointh (m)v (m/s)PEg (J)KE (J)E_mech (J)
P₁ (start)6.00.00117601176
P₂ (bottom)0.010.84011761176
P₃ (mid)3.07.675885881176

The three E_mech values are identical (1176 J), confirming conservation in the frictionless system.

Part 3 — With Friction (m = 60 kg, h_start = 6.0 m)

E_mech,initial: mgh = (60)(9.8)(6.0) = 3528 J

After one pass (returns to ~4.0 m): E_mech,final = (60)(9.8)(4.0) = 2352 J

Thermal energy generated: 3528 − 2352 = 1176 J

% Loss: (3528 − 2352)/3528 × 100 = 33.3%

Discussion

On the frictionless track the total mechanical energy was the same — 1176 J — at the start, the bottom, and the midpoint, so it was conserved to within reading precision: the potential energy lost in descending was exactly matched by the kinetic energy gained. The skater was fastest at the bottom (10.84 m/s), where PEg = 0 and all the energy was kinetic, and momentarily at rest at the top, where all the energy was potential.

With friction, the bar graph and pie chart showed a growing red "thermal" slice as the skater moved, and the skater rose to a lower height on the far side. The mechanical energy fell from 3528 J to 2352 J — a 33.3% loss — and exactly that 1176 J appeared as thermal energy, illustrating the first law of thermodynamics: the energy was not destroyed but converted to heat. The skater's acceleration is largest where the track curves most sharply at the bottom of the U, where the net upward (centripetal) force is greatest.

Conclusion

Mechanical energy was conserved on the frictionless track (constant E_mech at every point) and not conserved with friction, where the lost mechanical energy was fully accounted for as thermal energy. The results confirm the Law of Conservation of Energy.

Practice Questions

Show all work and include units. Use g = 9.8 m/s², KE = ½mv², PEg = mgh.

Question 1
A 50 kg skater starts from rest at a height of 8.0 m on a frictionless track. Find the total mechanical energy and the speed at the bottom.
Hint: E_mech = mgh; at the bottom all of it is KE, so v = √(2·KE/m).
Question 2
At a point where a frictionless skater is moving at 6.0 m/s and is 2.0 m high, the mass is 40 kg. Find KE, PEg, and E_mech.
Hint: add KE = ½mv² and PEg = mgh.
Question 3
A skater with 2000 J of mechanical energy loses 600 J to friction during a run. What is the final mechanical energy, and what percentage was lost?
Hint: E_mech,f = 2000 − 600; % loss = 600/2000 × 100.
Question 4
Explain, using the first law of thermodynamics, where the "missing" mechanical energy goes when a skater slows down due to friction.
Hint: total energy is conserved; mechanical energy converts to thermal energy (heat).
Question 5
On a frictionless track, at what point is the skater's kinetic energy greatest, and at what point is the potential energy greatest? Explain in terms of height and speed.
Hint: KE max at the lowest point (fastest); PEg max at the highest point (at rest).
Question 6 — Challenge
A 30 kg skater starts at 5.0 m. After several passes with friction it finally comes to rest at the bottom. How much total thermal energy was generated over the whole run?
Hint: all the initial mechanical energy mgh eventually becomes heat.