Investigate and verify the gas laws: Boyle's Law (pressure vs volume at constant temperature), Charles's Law (volume vs temperature at constant pressure), Gay-Lussac's Law (pressure vs temperature at constant volume), and how they combine into the ideal gas law PV = nRT. In each section, calculate the predicted value yourself first, then run the experiment and compare.
Theory — The Gas Laws
Boyle's Law
At constant temperature, the pressure of a fixed amount of gas is inversely proportional to its volume: squeeze the gas into half the volume and the pressure doubles.
Boyle's Law (constant T, n)
P × V = constant → P₁V₁ = P₂V₂
P₂ = P₁V₁ / V₂
Charles's Law
At constant pressure, the volume of a fixed amount of gas is directly proportional to its absolute (kelvin) temperature. Temperature must be in kelvin: T(K) = T(°C) + 273.15.
Charles's Law (constant P, n)
V / T = constant → V₁ / T₁ = V₂ / T₂
V₂ = V₁ × T₂ / T₁ (T in kelvin)
Gay-Lussac's Law
At constant volume, the pressure of a fixed amount of gas is directly proportional to its absolute temperature.
Gay-Lussac's Law (constant V, n)
P / T = constant → P₁ / T₁ = P₂ / T₂
P₂ = P₁ × T₂ / T₁ (T in kelvin)
The Ideal Gas Law
The three laws combine into one equation relating pressure, volume, amount, and temperature of an ideal gas.
Ideal Gas Law
P V = n R T, R = 0.08206 L·atm/mol·K (T in kelvin)
P = nRT/V · V = nRT/P · n = PV/RT
Boyle
P and V inversely related at constant T. P–V curve is a hyperbola.
Charles
V and T directly related at constant P. V–T line points to absolute zero.
Gay-Lussac
P and T directly related at constant V. P–T line points to absolute zero.
Law
Held constant
Relationship
Boyle's
T, n
P₁V₁ = P₂V₂
Charles's
P, n
V₁/T₁ = V₂/T₂
Gay-Lussac's
V, n
P₁/T₁ = P₂/T₂
Ideal gas
—
PV = nRT
Apparatus
The equipment a real ideal-gas-law experiment uses. In the simulation these are modelled for you, but the readings correspond to what each instrument would measure.
Gas syringe
Changes and reads the gas volume for Boyle's and Charles's laws.
Pressure gauge
Measures the gas pressure.
Thermometer
Measures the gas temperature in kelvin.
Water bath
Sets the gas temperature for the temperature-dependent laws.
Manometer
Reads pressure differences for the gas sample.
Analytical balance
Finds the moles of gas through its mass.
Instructions — Running the Virtual Experiment
The simulation has four sections, one for each law. In each one, calculate the predicted value yourself first, then run the experiment to check it, and record both values with screenshots. Prepare a short report for each of Boyle's, Charles's, and Gay-Lussac's laws (with a data table and graph).
Part 1 — Boyle's Law (Boyle's Law tab)
1
Open Simulation → Boyle's Law. Choose a fixed trial (initial P and V, new V at constant T). Calculate the new pressure yourself with P₂ = P₁V₁/V₂, type it in, then run and compare. Record the P–V data and sketch the P vs V graph.
Part 2 — Charles's Law (Charles's Law tab)
1
Open Charles's Law. Choose a fixed trial (initial V and T, new T at constant P). Calculate the new volume yourself with V₂ = V₁T₂/T₁ (kelvin), type it in, then check. Record the V–T data and graph.
Part 3 — Gay-Lussac's Law (Gay-Lussac's Law tab)
1
Open Gay-Lussac's Law. Choose a fixed trial (initial P and T, new T at constant V). Calculate the new pressure yourself with P₂ = P₁T₂/T₁ (kelvin), type it in, then check. Record the P–T data and graph.
Part 4 — Ideal Gas Law (Ideal Gas Law tab)
1
Open Ideal Gas Law. Choose what to solve for (P, V, or n), set the fixed values, calculate it yourself with PV = nRT, type it in, then check.
Simulation — Ideal Gas Laws
Gas Laws Virtual LabBoyle · Charles · Gay-Lussac · Ideal Gas
Boyle's Law — constant temperature
P₁ V₁ = P₂ V₂ Pressure and volume are inversely related
P V = n R T, R = 0.08206 L·atm/mol·K (T in kelvin)
Rearrange for the unknown
P = nRT ÷ V · V = nRT ÷ P · n = PV ÷ RT
P V = n R T
Step 1 — choose what to find
Step 2 — calculate, then check
Your answer—
Correct answer—
Choose the unknown, calculate it, type it, then check.
Team Questions
Question 1. A gas at 1.0 atm occupies 4.0 L. At constant temperature, what is the pressure when the volume is reduced to 2.0 L? (P₁V₁ = P₂V₂; type to 2 decimals)
Question 2. Boyle's Law describes the relationship between which two quantities, and is it direct or inverse? (Answer in a phrase)
Question 3. A gas occupies 2.0 L at 300 K. At constant pressure, what is its volume at 600 K? (V₁/T₁ = V₂/T₂; type to 2 decimals)
Question 4. Why must temperature be in kelvin when using Charles's or Gay-Lussac's law? (Answer in a phrase)
Question 5. A gas at 1.0 atm and 300 K is heated to 450 K at constant volume. What is the new pressure? (P₁/T₁ = P₂/T₂; type to 2 decimals)
Question 6. Using PV = nRT (R = 0.08206), find the pressure of 1.0 mol of gas at 273 K in a 22.41 L container. (Type to 2 decimals, in atm)
Question 7 — Challenge. Using PV = nRT, how many moles are in 24.45 L of gas at 1.0 atm and 298 K? (Type to 2 decimals)
Example Lab Report
Sample report for one of the three laws. Prepare a short report for each of Boyle's, Charles's, and Gay-Lussac's laws, each with a data table and a graph.
To verify Boyle's Law by showing that, at constant temperature, the product of pressure and volume of a fixed amount of gas is constant.
Variables
Controlled: temperature and amount of gas. Measured: pressure and volume.
Theory
At constant temperature, P and V are inversely proportional, so P₁V₁ = P₂V₂.
P₂ = P₁V₁ / V₂ · P × V = constant
Data and Worked Example
P (atm)
V (L)
P × V
1.00
4.00
4.00
2.00
2.00
4.00
4.00
1.00
4.00
Worked example: P₁ = 1.00 atm, V₁ = 4.00 L; at V₂ = 2.00 L, P₂ = (1.00 × 4.00)/2.00 = 2.00 atm. The product P × V stays at 4.00, confirming Boyle's Law.
Graph
A plot of P versus V gives a curve (hyperbola); a plot of P versus 1/V gives a straight line through the origin, confirming the inverse relationship.
Conclusion
The product of pressure and volume remained constant as the volume changed at fixed temperature, confirming Boyle's Law (P₁V₁ = P₂V₂).
Practice Questions
Show all work. Use P₁V₁ = P₂V₂, V₁/T₁ = V₂/T₂, P₁/T₁ = P₂/T₂ (T in kelvin), and PV = nRT with R = 0.08206.
Question 1
A gas at 2.0 atm occupies 3.0 L. At constant temperature, find the pressure when the volume increases to 6.0 L.
Hint: P₂ = (2.0 × 3.0)/6.0 = 1.0 atm.
Question 2
A gas occupies 3.0 L at 250 K. At constant pressure, find its volume at 500 K.
Hint: V₂ = 3.0 × 500/250 = 6.0 L.
Question 3
A gas at 2.0 atm and 250 K is heated at constant volume to 500 K. Find the new pressure.
Hint: P₂ = 2.0 × 500/250 = 4.0 atm.
Question 4
A sample of 0.50 mol of gas is at 300 K and 1.0 atm. Find its volume using PV = nRT.
Hint: V = nRT/P = (0.50 × 0.08206 × 300)/1.0 = 12.3 L.
Question 5
Convert 25 °C to kelvin, and explain why the kelvin scale is needed for the gas laws.
Hint: 25 + 273.15 = 298.15 K; ratios only work from absolute zero.
Question 6 — Challenge
2.0 mol of an ideal gas occupies 10.0 L at 350 K. Find the pressure, then explain how it would change if the volume were halved at constant temperature.
Hint: P = (2.0 × 0.08206 × 350)/10.0 = 5.74 atm; halving V doubles P (Boyle).
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