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Organic Chemistry · Reaction Mechanisms

Substitution and Elimination Mechanisms

Classify reactions as SN1, SN2, E1, or E2; build step-by-step mechanisms by clicking atoms, bonds, and lone pairs to place curved arrows showing electron flow; interpret kinetics and energy diagrams; and predict major products including stereochemistry and regiochemistry.

Theory — SN1, SN2, E1, E2

The Four Mechanisms

Alkyl halides (R–X) react with nucleophiles and bases by four canonical mechanisms that differ in the number of steps, the order of the rate law, and the stereochemistry. Which one dominates depends on the substrate, the nucleophile or base, the solvent, and the temperature.

SN2 — bimolecular substitution SN1 — unimolecular substitution E2 — bimolecular elimination E1 — unimolecular elimination
MechanismStepsRate lawStereoRegioKey feature
SN21 concertedk[RX][Nu]Inversion (Walden)Backside attack; 2 arrows
SN12 (ionise → trap)k[RX]RacemisationPlanar carbocation intermediate
E21 concertedk[RX][B]Anti-periplanarZaitsev (Hofmann with bulky base)3 arrows in one step
E12 (ionise → β-H loss)k[RX]ZaitsevShares step 1 with SN1

Curved Arrows — The Language of Mechanism

A curved arrow represents the movement of two electrons. The tail of the arrow starts where the electrons come from — a lone pair on an electron-rich atom, or a bond that is about to break. The head of the arrow ends where the electrons go — onto an electron-poor atom (forming a new bond or neutralising a charge) or into a new bond forming between two atoms.

Arrow tail/head conventions Tail FROM: a lone pair (Nu:, B:)  or  a bond that breaks (C–X, C–H)
Head TO: an atom (form a new bond / accept charge)  or  another bond (form a π-bond)
Every curved arrow moves exactly 2 electrons. All four mechanisms in this lab use only double-barbed (ionic) arrows; fishhook (radical) arrows are not used.

Mechanism 1 — SN2 (concerted, 2 arrows)

The nucleophile attacks carbon from the back side of the leaving group. In a single concerted transition state, the Nu–C bond forms while the C–X bond breaks.

SN2 — one step, two arrows Arrow 1:   Nu: lone pair  →  α-C (new Nu–C bond forms)
Arrow 2:   C–X bond  →  X (X takes the bonding electrons as it leaves)
Stereochemistry: inversion (Walden). Kinetics: rate = k [RX][Nu] — 2nd order overall, 1st order in each reactant.

Mechanism 2 — SN1 (stepwise, 2 arrows total)

Step 1 is the slow heterolysis of the C–X bond to give a carbocation and the leaving group. Step 2 is the fast attack of the nucleophile on the planar cation.

SN1 — step 1 (slow, RDS) Arrow:   C–X bond  →  X   (heterolysis to R⁺ + X⁻)
SN1 — step 2 (fast) Arrow:   Nu: lone pair  →  C⁺   (Nu captures the cation)
Stereochemistry: racemisation — the cation is planar (sp²) and is attacked on either face. Kinetics: rate = k [RX] — 1st order.

Mechanism 3 — E2 (concerted, 3 arrows)

In a single concerted step, a base removes a β-hydrogen while the leaving group departs. The C–H bond electrons form the new C=C π-bond.

E2 — one step, three arrows Arrow 1:   B: lone pair  →  β-H
Arrow 2:   Cβ–H bond  →  Cα–Cβ bond (forms the π bond)
Arrow 3:   Cα–X bond  →  X
Geometry: the β-H and the leaving group must be anti-periplanar (180°). Regiochemistry: Zaitsev (more substituted alkene) with small bases; Hofmann (less substituted) with bulky bases.

Mechanism 4 — E1 (stepwise, 3 arrows total)

Step 1 is identical to SN1 (ionisation to a carbocation). In step 2, a base — often the solvent — removes a β-H and the electrons form the new C=C π-bond.

E1 — step 1 (slow, RDS) Arrow:   C–X bond  →  X
E1 — step 2 (fast) Arrow 1:   B: lone pair  →  β-H
Arrow 2:   Cβ–H bond  →  Cα⁺ (forms π bond, neutralises cation)
Kinetics: rate = k [RX]. Regio: Zaitsev (thermodynamic; cation survives long enough to give the most stable alkene).

Choosing the Mechanism — Four Factors

Substrate

Methyl: SN2 only.
1°: SN2 (E2 with bulky base).
2°: any — depends on other factors.
3°: SN1, E1, or E2. Never SN2.

Nucleophile / Base

Strong Nu, weak base (I⁻, CN⁻, N₃⁻, RS⁻): SN2.
Strong Nu AND strong base (HO⁻, RO⁻): SN2 (1°), E2 (2°/3°).
Bulky strong base (tBuO⁻, DBU): E2 → Hofmann.
Weak Nu and weak base (H₂O, ROH — solvent only): SN1/E1.

Solvent

Polar aprotic (DMSO, DMF, acetone): favours SN2 — the anion is unsolvated and maximally reactive.
Polar protic (H₂O, ROH): favours SN1/E1 — stabilises cations/anions by H-bonding.

Temperature

Higher temperature favours elimination over substitution (entropy: one molecule → two fragments makes ΔS‡ more positive for elimination). Low T favours substitution.

Instructions — Running the Virtual Experiment

Section I — Classification Sorter

1
Twelve reactions appear in a pool at the top, and four empty bins below (SN2, SN1, E2, E1). Click a reaction card — it turns green. Then click the target bin to drop it.
2
If you change your mind, click a card inside a bin and it returns to the pool. When all 12 are placed, click Check All. Each card turns green (correct) or red (wrong) and a summary shows your score.

Section II — Interactive Mechanism Builder

1
Pick one of 12 mechanism examples from the selector (3 each for SN2, SN1, E2, E1). The workspace loads the first step with a fully-drawn substrate + reagents including atoms, bonds, and any lone pairs you can click.
2
To place an arrow: click a source (a lone pair "dot" or a bond) — it highlights. Then click a destination (an atom or another bond). A green arrow is drawn if the source→destination pair is correct, or a red arrow with explanation if it's a common wrong choice.
3
Each arrow you place is listed in the "Arrows placed" tracker. Click [×] next to an arrow to remove it if you want to try again. Arrows are placed until the step is complete (all correct arrows in place, no incorrect ones present).
4
For stepwise mechanisms (SN1, E1), when all arrows of step 1 are placed, click Next Step → to advance. The workspace shows the intermediate (carbocation + departed LG) and the arrows for step 2.
5
When every step is done, the example is marked as completed (green checkmark in the selector). The right-hand info panel shows the rate law, energy diagram, and stereochemistry outcome for that example.

Section III — Predict Products

1
Six reactions. For each, pick the major product from 3–4 options. Feedback explains stereochemistry (inversion / racemisation) or regiochemistry (Zaitsev / Hofmann) as relevant.

Simulation

SN1 / SN2 / E1 / E2 Virtual Lab | Section I — Classification Sorter
Sort each of the 12 reactions into the correct mechanism bin (SN2, SN1, E2, E1). Click a reaction card to select it, then click the target bin to drop it in. Click a card inside a bin to return it to the pool.
Reaction pool (click a card, then click a bin):
SN2
SN1
E2
E1
Pick an example, then click atoms, bonds, and lone pairs to draw the curved arrows of each mechanism step. Green arrows = correct; red = a common wrong choice. Completed examples get a green check.

Select a mechanism example

Click atoms, bonds, or lone pairs to place arrows.
Arrows placed in this step
Watching the correct mechanism
Kinetics & rate law
Energy diagram
Stereo / regio outcome
Predict the major organic product.
1 of 6
Reaction setup
Major product (pick one)

Team Questions

Question 1. A student observes that the rate of 1-bromobutane + NaI in acetone doubles when [I⁻] is doubled. What mechanism is this, and what is the rate law?
Question 2. Why is (CH₃)₃CBr unreactive toward SN2 but very reactive toward SN1 and E1? Give the two structural reasons.
Question 3. In the SN1 energy diagram, what does the valley between the two peaks represent, and why is the first peak higher than the second?
Question 4. Why does (R)-2-bromobutane + NaCN in DMSO give (S)-2-cyanobutane (inversion), while (R)-2-bromo-2-methylbutane + EtOH gives a racemic alcohol? Name each mechanism.
Question 5. 2-bromobutane + NaOEt gives 2-butene (Zaitsev); the same substrate with tBuOK gives 1-butene (Hofmann). Why does the bulky base change the regiochemistry?

Example Lab Report

Substitution and Elimination Mechanisms

Chemistry 221 | Section: [Your Section] | Date: [Date]

Lab Members: [Names of all members present]

Purpose

To distinguish between the four canonical mechanisms of alkyl halide reactions (SN1, SN2, E1, E2) from substrate, nucleophile/base, solvent, and temperature; to draw complete curved-arrow mechanisms showing electron flow at each step; to relate the number of steps and rate law to the energy diagram; and to predict major products including stereochemistry and regiochemistry.

Theory

Alkyl halides R–X react with nucleophiles or bases by four mechanisms that differ in molecularity. In SN2 and E2 the rate-determining step is a single concerted transition state; both the substrate and the Nu/base appear in the rate law, giving 2nd-order kinetics. In SN1 and E1, ionisation of the C–X bond to a carbocation is the slow step; the nucleophile/base is involved only in a fast subsequent step, so the rate is 1st order in substrate only. The dominant mechanism is controlled by the substrate (methyl/1°/2°/3°), the nucleophile/base (strong Nu weak base → SN2; strong base → E2; bulky strong base → E2 Hofmann; weak Nu/base → SN1/E1), the solvent (polar aprotic → SN2, polar protic → SN1/E1), and the temperature (heat → elimination).

Curved arrows show the flow of electron pairs. Each arrow starts from a lone pair or a bond (the electron source) and ends at an atom or a bond (the destination). SN2 uses two arrows in one step; SN1 uses two arrows across two steps; E2 uses three arrows in one concerted step; E1 uses three arrows across two steps.

Stereochemistry: SN2 gives inversion at the α-carbon (Walden inversion — the Nu attacks from the back face of the LG). SN1 goes via a planar sp² carbocation that is attacked on either face, giving racemic product. E2 requires the β-H and LG to be anti-periplanar (180° dihedral). Regiochemistry: with small bases, E1 and E2 give the more-substituted (Zaitsev) alkene; with bulky bases (tBuO⁻, DBU), E2 gives the less-substituted (Hofmann) alkene.

Calculations / Analysis

Sample analysis — (R)-2-bromobutane + NaCN in DMSO at 25 °C:

Substrate: 2° (2-BrBu). Nu: CN⁻ (strong Nu, weak base). Solvent: DMSO (polar aprotic). T: RT.
Strong Nu, weak base, polar aprotic → SN2. Concerted backside attack gives inversion: (R) → (S). Rate law: rate = k [RX][CN⁻] (2nd order). Product: (S)-2-cyanobutane, enantiopure.
Energy diagram: one hump (single TS). No intermediate. Arrows: (1) CN⁻ lone pair → α-C; (2) C–Br bond → Br.

Sample analysis — (CH₃)₃CBr + H₂O:

Substrate: 3°. Nu: water (weak). Solvent: water (polar protic). T: RT.
Tertiary substrate with weak Nu in protic solvent → SN1. Two-step: ionise to (CH₃)₃C⁺ + Br⁻; water traps the cation from either face (racemisation, though not observable on an achiral substrate); deprotonation gives alcohol.
Rate law: rate = k [(CH₃)₃CBr]. Arrows step 1: C–Br → Br. Arrows step 2: water lone pair → C⁺.
Energy diagram: two humps, TS1 > TS2, valley is the carbocation intermediate.

Results Table

Section I — classification of 12 reactions

ReactionSubstrateNu/BaseSolventTMechanism
1-BrBu + NaCNStrong NuDMSORTSN2
(R)-2-BrBu + N₃⁻Strong NuDMFRTSN2
MeI + NaSHmethylStrong NuacetoneRTSN2
tBuBr + H₂OWeak NuH₂ORTSN1
3-Br-3-Me-hexane + MeOHWeak NuMeOHRTSN1
2-Cl-2-Me-propane + EtOHWeak NuEtOHRTSN1
2-BrBu + NaOEt (hot)Strong baseEtOH80°CE2
1-ClPr + tBuOKBulky basetBuOHRTE2
CyBr + NaOHStrong baseEtOHRTE2
tBuI + EtOH (hot)Weak baseEtOH60°CE1
2-I-2-Me-butane + AcOHWeak baseAcOH80°CE1
3-Me-3-BrC₅ + H₂O (hot)Weak baseH₂O70°CE1

Section II — mechanism summary for the 12 built examples

MechanismStepsRate lawTotal arrowsStereochemistry
SN21k [RX][Nu]2Inversion
SN12k [RX]2Racemisation
E21k [RX][B]3Anti-periplanar
E12k [RX]3Planar cation, Zaitsev

Discussion

The sorter in Section I demonstrated how the four factors combine to determine mechanism. Primary substrates with strong non-basic nucleophiles in polar aprotic solvents (1-BrBu + NaCN/DMSO, MeI + NaSH/acetone) are the clearest SN2 cases. Tertiary substrates in polar protic solvents with no strong base (tBuBr + H₂O, 3-Br-3-Me-hexane + MeOH) give SN1. Adding a strong base to a tertiary substrate tips to E2 (tBuBr + NaOEt hot), while a tertiary substrate heated with only solvent acting as base gives E1 (tBuI + EtOH hot). The trickiest case — primary substrate with a bulky base (1-ClPr + tBuOK) — gives E2 instead of SN2 because tBuO⁻ is too large to approach the α-carbon.

Section II's interactive arrow placement showed that all four mechanisms can be described in the same "curved arrow" language, and the number of arrows equals the number of electron-pair movements. SN2 uses 2 arrows in 1 step. SN1 uses 2 arrows in 2 steps. E2 uses 3 arrows in 1 step (base grabs β-H, C-H electrons form π-bond, C-X breaks). E1 uses 3 arrows in 2 steps (first step same as SN1 ionisation, then 2 arrows in step 2 to eliminate).

The kinetics and energy diagram directly follow: concerted mechanisms (SN2, E2) have one TS → 2nd-order kinetics; stepwise (SN1, E1) have two TSs with a carbocation intermediate between them → 1st-order kinetics (because ionisation, the RDS, only involves the substrate). Section III confirmed that once mechanism is known, the major product follows from its stereochemistry and regiochemistry rules.

Conclusion

Classified all 12 reactions correctly using the four-factor analysis (substrate, Nu/base, solvent, T). Built full arrow-pushing mechanisms for 12 examples (3 each for SN2, SN1, E2, E1) showing 2 arrows in 1 step (SN2), 2 arrows in 2 steps (SN1), 3 arrows in 1 step (E2), and 3 arrows in 2 steps (E1). Predicted products for 6 reactions with correct stereo/regio outcomes (inversion for SN2, racemic for SN1, Zaitsev for E2/E1 small base, Hofmann for E2 bulky base). Results consistent with textbook predictions throughout.

Practice Questions

Question 1
Draw the full arrow-pushing mechanism for each: (a) (R)-2-iodopentane + NaN₃ in DMF; (b) 1-bromo-3-methylbutane + tBuOK; (c) 2-Br-2,3-dimethylbutane + H₂O.
Hint: (a) 2° + strong Nu + aprotic → SN2 (2 arrows, inversion); (b) 1° + bulky base → E2 (3 arrows, Hofmann); (c) 3° + weak Nu/base → SN1 (2 steps, 2 arrows, racemic).
Question 2
A reaction has rate = k [RX] = 3.5 × 10⁻³ s⁻¹. Doubling [Nu] does not change the rate. Which mechanism(s) fit? How could you tell SN1 from E1?
Hint: 1st-order kinetics fit SN1 or E1 (same ionisation RDS). Distinguish by isolating the product: alcohol/substituted compound = SN1, alkene = E1, or both in a ratio.
Question 3
Draw the curved-arrow mechanism for 2-Br-propane + NaSH in acetone. Sketch the transition state showing the backside approach of HS⁻ and the trigonal-bipyramidal arrangement.
Hint: SN2 with two arrows. Source of arrow 1: HS⁻ lone pair. Destination: α-C. Source of arrow 2: C–Br bond. Destination: Br.
Question 4
3-Br-3-methylhexane is heated in water. (a) Identify all three possible products. (b) Which is the major alkene (Zaitsev or Hofmann)? (c) What's the stereochemistry of the alcohol?
Hint: SN1 + E1 competing. Products: 3-methyl-3-hexanol (racemic, via SN1); 3-methyl-2-hexene (Zaitsev alkene via E1, major elimination product); 3-methyl-1-hexene (less stable alkene, minor).
Question 5
Sketch the energy diagram for (CH₃)₃CBr + EtOH → (CH₃)₃COEt + HBr. Label reactants, TS1, carbocation intermediate, TS2, and products. Which TS is the RDS?
Hint: Two humps. TS1 (ionisation) is highest — it's the RDS. The valley between the humps is the carbocation R⁺. TS2 is lower (Nu capture is fast and exothermic).
Question 6 — Challenge
cis-1-Br-4-tert-butylcyclohexane undergoes E2 with NaOEt ~500× faster than the trans isomer. Explain with conformational analysis.
Hint: tBu is locked equatorial (A-value 22 kJ/mol). Cis: Br and tBu on opposite faces → Br forced axial → anti-periplanar H available (axial on adjacent C). Trans: Br equatorial → no anti-periplanar β-H accessible, must use slower gauche geometry or SN2-like path.