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Modern Physics · Photoelectric Effect · Part 2

Photoelectric Effect — Light Intensity

Hold the light frequency fixed above the threshold and change only its intensity. Measure how the photocurrent — the rate at which electrons are emitted — responds, and confirm that the maximum kinetic energy of those electrons does not change at all. The result reveals the particle nature of light: intensity sets the number of photons, not the energy each one carries.

Theory — Intensity, Photon Count, and Photocurrent

Objectives
  • Discuss the photoelectric effect and how it relates to quantum theory.
  • Solve problems involving light intensity and electron emission.
  • Show that photocurrent is proportional to intensity while electron energy is not.

What "Intensity" Means for a Beam of Photons

The intensity of a light beam is the energy it delivers per second per unit area — how bright it is. In the photon picture, brightening a beam (at a fixed colour) means sending more photons per second, each still carrying the same energy E = hf. Intensity changes the photon count, never the energy per photon.

Intensity in the Photon Picture Intensity ∝ (number of photons per second) × (energy per photon)
At fixed frequency: energy per photon is constant, so
Intensity ∝ number of photons per second

Photocurrent

Above the threshold frequency, each photon can free one electron. If you double the number of photons arriving each second, you double the number of electrons ejected each second — and the electric current they produce. The photocurrent is therefore directly proportional to the light intensity.

Photocurrent vs Intensity (above threshold) I_photo ∝ intensity  (a straight line through the origin)

more photons/s → more electrons/s → larger current
Double the intensity → double the photocurrent

Why the Kinetic Energy Does NOT Change

Each electron is freed by absorbing a single photon. Since every photon in the beam has the same energy (the frequency hasn't changed), every freed electron gets the same energy budget, and the maximum kinetic energy KE_max = hf − ϕ is unchanged no matter how bright the light is. Brighter light makes more electrons, not faster ones.

Energy Is Set by Frequency, Not Intensity KE_max = h·f − ϕ  → depends only on f (and the metal), not on intensity
Stopping voltage V_stop = KE_max / e  → also independent of intensity
Intensity ↑ : current ↑, but KE_max and V_stop stay the same

Why This Defeats the Wave Picture

If light were purely a wave, a brighter beam would pour more energy into each electron, so the electrons should come out faster (higher KE). They don't. Instead, brightness only changes how many electrons appear, while their maximum energy is fixed by frequency. This is direct evidence that light arrives in discrete energy packets — photons — and is one of the foundations of quantum theory.

Raise the intensity (this lab)

More photons per second → more electrons per second → larger photocurrent. KE_max and stopping voltage are unchanged.

Raise the frequency (Part 1)

More energetic photons → larger KE_max and stopping voltage. Studied in the Work Function lab (Part 1).

Quantity changedPhotocurrentMax kinetic energyConclusion
Intensity ↑ (fixed f)increases (∝ intensity)no changemore electrons, same energy
Frequency ↑ (fixed intensity)≈ same numberincreasessame count, faster electrons
Frequency below thresholdzerononeno emission at any intensity

Instructions — Running the Virtual Experiment

Use the built-in simulation to investigate how light intensity affects the number of electrons emitted while the frequency is kept constant. Record every reading in your lab notebook; include your current-versus-intensity graph in your report.

Experiment 1 — Watching the Beam Brighten (Apparatus tab)
1
Open Simulation → Apparatus. The wavelength is set to 300 nm (above sodium's threshold). Slowly raise the intensity slider and watch the photon stream and the ejected-electron stream both get denser.
2
As you raise the intensity, watch the photocurrent climb while the KE_max and stopping voltage readouts stay fixed. The electrons do not speed up — there are simply more of them.
3
Now drag the wavelength to a longer value past the threshold — e.g. 600 nm, where each photon carries only 1240/600 = 2.07 eV, which is below sodium's 2.28 eV work function. (A longer wavelength means a lower photon energy, so although 600 is a bigger number than 300, it is the below-threshold case.) Raise the intensity to 100% and confirm the photocurrent stays at 0 nA — brightness cannot rescue too-low photon energy.
Experiment 2 — Photocurrent vs Intensity (Measurements tab)
1
Open Measurements (wavelength fixed at 300 nm, above threshold). Click each intensity button (20–100%) and then Record reading. Both the photocurrent and KE_max are logged.
2
Click Plot & check. The current-versus-intensity points should fall on a straight line through the origin (current ∝ intensity), and the KE_max column should be identical for every row.
3
In your report, state the constant ratio of current to intensity and explain, using the photon model, why KE_max never changed while the current did.

Simulation — Intensity & Photoelectron Emission

Photoelectric Effect — Light Intensity Virtual LabVary the intensity at fixed frequency
photons (count ∝ intensity)
ejected electrons
Same colour throughout — frequency is fixed.

Controls

Readout
Intensity— %
Photocurrent— nA
Electrons / s
KE_max (fixed)— eV
Stopping V (fixed)— V
Each point is one (intensity, photocurrent) reading.
A straight line through the origin means current ∝ intensity.

Fixed: 300 nm on Sodium

Frequency is held constant above threshold; only intensity changes.

Set intensity

Current reading (20%)
Photocurrent— nA
KE_max— eV
Intensity (%)Photocurrent (nA)KE_max (eV)
No readings yet — pick an intensity and click "Record reading".

Team Questions

Question 1. A beam of fixed-frequency light (above threshold) produces a photocurrent of 40 nA. If you double the light intensity without changing the frequency, what photocurrent do you expect? (Type just the number in nA)
Question 2. When you double the intensity in Question 1, what happens to the maximum kinetic energy of the ejected electrons — does it increase, decrease, or stay the same? (One word)
Question 3. At a fixed frequency, what does increasing the light intensity primarily increase — the energy of each photon, or the number of photons arriving per second? (Answer "energy" or "number")
Question 4. Light whose frequency is below the metal's threshold shines on the surface. You crank the intensity up to maximum. What photocurrent results? (Type just the number in nA)
Question 5. When photocurrent is plotted against light intensity (above threshold), what is the shape of the graph? (Describe in a few words — what kind of line, and does it pass through the origin?)
Question 6. In a trial, 40% intensity gives a photocurrent of 40 nA. Assuming the proportional relationship holds, what photocurrent would 70% intensity produce? (Type just the number in nA)
Question 7 — Challenge. A student wants the ejected electrons to come out with more kinetic energy. Should they increase the intensity of the light, or change something else? Name the quantity they must change. (One word)

Example Lab Report

Sample report demonstrating the expected format and level of detail. Use as a guide for your own submission.

Photoelectric Effect — The Effect of Light Intensity on Electron Emission

Physics | Section: [Your Section] | Date: [Date]

Lab Members: [Names of all members present]

Purpose

To investigate how the intensity of light affects the photoelectric emission of electrons while the frequency is held constant, by measuring the photocurrent at several intensities and confirming that the maximum kinetic energy of the electrons is independent of intensity. The result tests the particle (photon) model of light.

Theory

At a fixed frequency above the threshold, each photon carries the same energy E = hf and frees one electron with maximum kinetic energy KE_max = hf − ϕ. Increasing the intensity increases the number of photons arriving per second, so it increases the number of electrons emitted per second and the photocurrent, but it does not change the energy delivered to any individual electron.

Intensity ∝ photons per second (at fixed f)
Photocurrent ∝ intensity  (line through origin)
KE_max = hf − ϕ  (independent of intensity)

If light behaved purely as a wave, brighter light would transfer more energy to each electron and raise KE_max. The photon model instead predicts a higher count of equally energetic electrons — exactly what is observed.

Calculations — Sample: Sodium (ϕ = 2.28 eV) at λ = 300 nm

Photon energy: E = 1240/300 = 4.13 eV (above the 2.28 eV work function, so emission occurs at every intensity)

Maximum kinetic energy: KE_max = 4.13 − 2.28 = 1.85 eV — the same value at every intensity

Current–intensity ratio: I_photo / intensity = 80 nA / 80% = 1.0 nA per % — constant across the data set, confirming proportionality

Results Table — Photocurrent and KE_max vs Intensity (λ = 300 nm, Sodium)

Intensity (%)Photocurrent (nA)I / intensity (nA/%)KE_max (eV)
20201.01.85
40401.01.85
60601.01.85
80801.01.85
1001001.01.85

Discussion

The photocurrent rose in direct proportion to the light intensity: doubling the intensity from 40% to 80% doubled the current from 40 nA to 80 nA, and the ratio of current to intensity stayed constant at 1.0 nA per percent. A graph of photocurrent against intensity was therefore a straight line passing through the origin — when the light is off (0% intensity) there is no current.

Critically, the maximum kinetic energy stayed fixed at 1.85 eV across the entire range of intensities, because the frequency — and hence the energy of each photon — never changed. Brighter light produced more electrons, not faster ones. Below the threshold frequency, raising the intensity to maximum produced no current at all. Together these observations cannot be explained by a wave model, in which more intense light should deliver more energy to each electron; they confirm that light is absorbed as discrete photons.

Conclusion

The experiment confirmed that, at a fixed frequency above threshold, photocurrent is directly proportional to light intensity while the maximum kinetic energy of the photoelectrons is independent of intensity. Intensity controls the number of photons (and therefore electrons), not the energy of each one — direct evidence for the particle nature of light and a cornerstone of quantum theory.

Practice Questions

Show all work or give a clear explanation for each answer.

Question 1
A fixed-frequency light source produces a photocurrent of 25 nA at 50% intensity. Predict the photocurrent at 100% intensity and at 10% intensity, assuming the proportional relationship holds.
Hint: current ∝ intensity. The ratio current/intensity is constant.
Question 2
Explain, using the photon model, why tripling the intensity of a beam triples the number of electrons emitted per second but leaves their maximum kinetic energy unchanged.
Hint: intensity sets photons/second; each photon still has energy hf, so each electron still receives the same hf − ϕ.
Question 3
300 nm light shines on sodium (ϕ = 2.28 eV). State the maximum kinetic energy of the electrons. Would this value change if the intensity were increased tenfold? Explain.
Hint: KE_max = 1240/300 − 2.28. Intensity does not appear in this equation.
Question 4
A very bright source of 650 nm red light is aimed at zinc (ϕ = 4.30 eV, threshold ≈ 288 nm). Describe the photocurrent as the intensity is increased from low to very high. Explain your answer.
Hint: compare the photon energy (1240/650) to ϕ. If below threshold, no intensity produces a current.
Question 5
Sketch two graphs for an above-threshold beam: (a) photocurrent versus intensity, and (b) maximum kinetic energy versus intensity. Describe the shape of each and what it tells you about light.
Hint: (a) is a straight line through the origin; (b) is a horizontal line (constant). Together they show intensity controls count, not energy.
Question 6 — Challenge
A student observes that doubling the intensity doubles the photocurrent, but they want to also double the maximum kinetic energy of the electrons. For sodium (ϕ = 2.28 eV) illuminated at 400 nm (KE_max = 0.82 eV), find a new wavelength that would double KE_max to 1.64 eV. Does changing intensity help at all?
Hint: need E = KE_max + ϕ = 1.64 + 2.28 = 3.92 eV → λ = 1240/3.92. Intensity cannot change KE_max — only frequency can.