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Modern Physics · Photoelectric Effect · Part 1

Photoelectric Effect — Work Function

Shine light of different frequencies on a metal surface and measure the maximum kinetic energy of the ejected electrons. Plot kinetic energy against frequency to recover the work function of four metals, the threshold frequency, and the value of Planck's constant — the experiment that revealed the particle nature of light.

Theory — Photons, Work Function, and the Threshold

Objectives
  • Discuss the principles and applications of the photoelectric effect.
  • Solve problems relating photon energy, work function, and electron ejection.
  • Determine the work function of a metal from kinetic-energy-versus-frequency data.

Light as Photons

In the photoelectric effect, light striking a metal surface ejects electrons. The surprising result, explained by Einstein in 1905, is that light delivers its energy in discrete packets called photons. The energy of a single photon depends only on its frequency f (or equivalently its wavelength λ), not on how bright the light is.

Photon Energy E = h·f = h·c / λ

h = 6.626 × 10⁻³⁴ J·s (Planck's constant)
c = 3.00 × 10⁸ m/s
Convenient form: E (eV) = 1240 / λ (nm)

Work Function and the Threshold Frequency

Each metal binds its electrons with a minimum energy called the work function ϕ. A photon must carry at least this much energy to free an electron. If the photon energy is below ϕ, no electron is ejected no matter how intense the light. The frequency at which a photon's energy exactly equals ϕ is the threshold frequency f₀; the matching wavelength is the threshold wavelength λ₀.

Threshold Condition Emission occurs only when  h·f ≥ ϕ
Threshold frequency:  f₀ = ϕ / h
Threshold wavelength:  λ₀ = h·c / ϕ = 1240 / ϕ(eV) nm
Below f₀ : no electrons. Above f₀ : electrons ejected.

Einstein's Photoelectric Equation

When a photon with more than enough energy is absorbed, the excess appears as kinetic energy of the ejected electron. The most energetic electrons carry the full surplus:

Einstein's Photoelectric Equation KE_max = h·f − ϕ

Measured with a stopping voltage:  e·V_stop = KE_max
So  V_stop = (h·f − ϕ) / e  (and KE_max in eV equals V_stop in volts)
A plot of KE_max vs f is a straight line: slope = h, intercept = −ϕ

Reading the KE-vs-Frequency Graph

Einstein's equation has the form of a straight line, y = mx + b, with KE_max on the y-axis and frequency on the x-axis. The slope of that line is Planck's constant h, the y-intercept is −ϕ (so the work function is read off directly), and the x-intercept is the threshold frequency f₀. Remarkably, the slope is the same for every metal — only the intercept shifts — which is exactly what the photon model predicts.

Raise the frequency

Above threshold, higher frequency means more energetic photons, so KE_max and the stopping voltage increase. The slope of KE vs f stays fixed at h.

Raise the intensity

Brighter light at the same frequency sends more photons, so more electrons are ejected — but each electron's maximum kinetic energy is unchanged. (Intensity is the subject of Part 2.)

MetalWork function ϕ (eV)Threshold λ₀ (nm)Threshold f₀ (Hz)
Sodium (Na)2.285445.51 × 10¹⁴
Calcium (Ca)2.874326.94 × 10¹⁴
Zinc (Zn)4.302881.04 × 10¹⁵
Copper (Cu)4.702641.14 × 10¹⁵

Instructions — Running the Virtual Experiment

Use the built-in simulation to investigate how the frequency of light affects electron emission, and to determine the work function of four metals. Record every reading in your lab notebook; include your KE-versus-frequency graph and calculations in your report.

Experiment 1 — Finding the Threshold (Apparatus tab)
1
Open Simulation → Apparatus and choose Sodium. Start with a long wavelength (low frequency), around 600 nm.
2
Slowly decrease the wavelength (raise the frequency) until electrons just begin to be ejected. Record the threshold wavelength λ₀ where emission starts, and compare it to λ₀ = 1240/ϕ.
3
Confirm that increasing the intensity below threshold still produces no electrons — brightness cannot make up for too little photon energy.
Experiment 2 — Kinetic Energy vs Frequency (Measurements tab)
1
Open Measurements and select a metal. Click each wavelength button (200–360 nm). Readings below the metal's threshold will be rejected — only above-threshold points are recorded.
2
Click Record reading at each wavelength to log the frequency f and the maximum kinetic energy KE_max (equal to the stopping voltage).
3
With at least three points recorded, click Plot & fit. The best-fit line gives the slope (Planck's constant h), the y-intercept (−ϕ, so the work function), and the x-intercept (the threshold frequency f₀).
Experiment 3 — Four Metals (Measurements tab)
1
Repeat Experiment 2 for all four metals (Sodium, Calcium, Zinc, Copper). Reset between metals.
2
Record the work function obtained from each fit and compare it to the accepted value. Confirm that the slope (h) comes out the same for every metal — only the intercept changes. Tabulate your results in the report.

Simulation — Photoelectric Apparatus & KE-vs-Frequency Plot

Photoelectric Effect — Work Function Virtual LabChoose a metal and vary the light frequency
photons (colour = wavelength)
ejected electrons
metal cathode

Controls

Readout
Photon energy— eV
Frequency f— Hz
Work function ϕ— eV
KE_max— eV
Stopping voltage— V
Each point is one (frequency, KE_max) reading.
Slope = h · y-intercept = −ϕ · x-intercept = f₀

Metal

Set wavelength

Current reading (nm = 200)
Frequency f— Hz
KE_max— eV
λ (nm)f (×10¹⁴ Hz)KE_max (eV)
No readings yet — pick a wavelength above threshold and click "Record reading".

Team Questions

Question 1. Light of wavelength 400 nm strikes a metal. What is the energy of each photon in electron-volts? Use E = 1240/λ(nm). (Type just the number in eV, e.g. 3.10)
Question 2. That 400 nm light (3.10 eV per photon) hits sodium, whose work function is 2.28 eV. What is the maximum kinetic energy of the ejected electrons? Use KE_max = E − ϕ. (Type just the number in eV)
Question 3. For that same case, what stopping voltage would just halt the most energetic electrons? (Type just the number in volts)
Question 4. Copper has a work function of 4.70 eV. What is its threshold wavelength λ₀ — the longest wavelength that can still eject electrons? Use λ₀ = 1240/ϕ. (Type just the number in nm, e.g. 264)
Question 5. Zinc has a work function of 4.30 eV (threshold ≈ 288 nm). If 500 nm green light shines on zinc, are any electrons ejected? (Answer "yes" or "no")
Question 6. When you plot maximum kinetic energy (y-axis) against light frequency (x-axis), what physical constant does the slope of the straight line represent? (Name it)
Question 7 — Challenge. Two metals, A and B, are each tested and their KE-vs-frequency lines are plotted. The lines are parallel but B's line is shifted to the right. Which metal has the larger work function — A or B? (Answer "A" or "B")

Example Lab Report

Sample report demonstrating the expected format and level of detail. Use as a guide for your own submission.

Photoelectric Effect — Determining the Work Functions of Four Metals

Physics | Section: [Your Section] | Date: [Date]

Lab Members: [Names of all members present]

Purpose

To investigate how the frequency of incident light controls the kinetic energy of photoelectrons, to determine the work function of four metals (sodium, calcium, zinc, and copper) from kinetic-energy-versus-frequency graphs, and to verify that the slope of each graph yields Planck's constant.

Theory

A photon of frequency f carries energy E = hf. When it is absorbed by an electron in a metal, the electron escapes only if the photon energy exceeds the work function ϕ; the surplus becomes kinetic energy. Einstein's photoelectric equation has the form of a straight line in f.

KE_max = h·f − ϕ  (y = m·x + b)
slope m = h · y-intercept = −ϕ · x-intercept f₀ = ϕ/h
E(eV) = 1240 / λ(nm) · V_stop = KE_max / e

Plotting KE_max against f therefore gives a line whose slope is Planck's constant (the same for every metal) and whose intercept reveals the work function of the particular metal.

Calculations — Sample: Sodium (ϕ = 2.28 eV) at λ = 400 nm

Photon energy: E = 1240/400 = 3.10 eV

Maximum kinetic energy: KE_max = 3.10 − 2.28 = 0.82 eV

Stopping voltage: V_stop = KE_max/e = 0.82 V

Slope from two points (300 nm and 400 nm): m = (1.853 − 0.820) eV / (1.000 − 0.750)×10¹⁵ Hz = 4.13 × 10⁻¹⁵ eV·s. Converting: h = m·e = (4.13 × 10⁻¹⁵)(1.602 × 10⁻¹⁹) = 6.62 × 10⁻³⁴ J·s ✓

Results Table — Sodium KE_max vs Frequency

λ (nm)f (×10¹⁴ Hz)E = hf (eV)KE_max (eV)V_stop (V)
30010.004.131.851.85
3508.573.541.261.26
4007.503.100.820.82
4506.672.760.480.48
5006.002.480.200.20
MetalMeasured ϕ (eV)Accepted ϕ (eV)Measured slope h (J·s)
Sodium2.282.286.62 × 10⁻³⁴
Calcium2.872.876.62 × 10⁻³⁴
Zinc4.304.306.62 × 10⁻³⁴
Copper4.704.706.62 × 10⁻³⁴

Discussion

For every metal the maximum kinetic energy rose linearly with frequency, exactly as KE_max = hf − ϕ predicts. The slope of each line was 6.62 × 10⁻³⁴ J·s, agreeing with the accepted value of Planck's constant (6.626 × 10⁻³⁴ J·s) and — crucially — coming out the same regardless of which metal was used. This is the signature of the photon model: the energy carried per photon depends only on frequency, not on the target.

The y-intercept of each line gave the work function directly: 2.28 eV for sodium, 2.87 eV for calcium, 4.30 eV for zinc, and 4.70 eV for copper, all matching their accepted values. Below each metal's threshold frequency no electrons were emitted, and increasing the light intensity below threshold made no difference — confirming that a single photon, not the accumulated brightness, must supply the escape energy. This behaviour cannot be explained by treating light purely as a wave.

Conclusion

The experiment confirmed Einstein's photoelectric equation. Maximum kinetic energy was linear in frequency with slope equal to Planck's constant, the threshold frequency marked the onset of emission, and the work functions extracted from the intercepts matched accepted values for all four metals. The results support the particle (photon) model of light.

Practice Questions

Show all work and include units in your answers.

Question 1
Light of wavelength 250 nm strikes a calcium surface (ϕ = 2.87 eV). Find the photon energy, the maximum kinetic energy of the ejected electrons, and the stopping voltage.
Hint: E = 1240/λ; KE_max = E − ϕ; V_stop = KE_max/e (numerically equal in eV/V).
Question 2
A metal has a threshold wavelength of 350 nm. What is its work function in eV? What is its threshold frequency in Hz?
Hint: ϕ = 1240/λ₀ (eV). f₀ = c/λ₀.
Question 3
In a photoelectric experiment, a KE-versus-frequency graph has a slope of 6.6 × 10⁻³⁴ J·s and crosses the frequency axis at 9.0 × 10¹⁴ Hz. What is the work function of the metal in joules and in eV?
Hint: at the x-intercept KE = 0, so ϕ = h·f₀. Convert J to eV by dividing by 1.602 × 10⁻¹⁹.
Question 4
Monochromatic light ejects electrons from sodium (ϕ = 2.28 eV) with a maximum kinetic energy of 1.50 eV. What is the wavelength of the light?
Hint: E = KE_max + ϕ. Then λ = 1240/E (nm).
Question 5
Explain why shining a very bright red laser (650 nm) on zinc (ϕ = 4.30 eV) ejects no electrons, while even a dim ultraviolet lamp (250 nm) does. Use photon energy in your explanation.
Hint: compare each photon's energy (1240/λ) to ϕ. Brightness adds more photons, not more energy per photon.
Question 6 — Challenge
When 300 nm light shines on an unknown metal, the stopping voltage is 1.10 V. When 250 nm light is used, the stopping voltage is 2.09 V. Use these two data points to determine Planck's constant (in J·s) and the work function of the metal (in eV).
Hint: KE_max = eV_stop = hf − ϕ. Subtract the two equations to eliminate ϕ and solve for h; then back-substitute for ϕ.