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Waves · Resonance on a String

Standing Waves and String Harmonics

Send a pulse down a string to measure the wave speed, then drive the string at just the right frequencies to lock in standing-wave patterns. Find the first, second, and third harmonics, measure their wavelengths and frequencies, and see how tension changes the wave speed and the resonant frequencies.

Theory — Standing Waves on a String

Waves on a String

A disturbance sent along a stretched string travels at a wave speed v that depends on how tightly the string is stretched. A tighter (higher-tension) string carries waves faster. The wave speed links the frequency f (how often the string vibrates) and the wavelength λ (the length of one full wave).

Wave Speed v = f · λ   and   v = √(T / μ)

v = wave speed (m/s), f = frequency (Hz), λ = wavelength (m)
T = tension (N), μ = mass per unit length (kg/m)
Higher tension → faster waves

Standing Waves and Resonance

When a string is fixed at both ends and driven at just the right frequency, the wave reflected from the far end overlaps the incoming wave so that the pattern appears to stand still. Points that never move are nodes; points that swing with the largest amplitude are anti-nodes. This only happens at special resonant frequencies; at any other frequency the reflections do not line up and the string looks messy.

Harmonics

For a string of length L fixed at both ends, a whole number of half-wavelengths must fit between the ends. This gives a series of allowed patterns called harmonics. The n-th harmonic has n anti-nodes.

Harmonic Series (both ends fixed) Wavelength: λ_n = 2L / n
Frequency:  f_n = n · v / (2L) = n · f₁

n = 1, 2, 3, … (harmonic number = number of anti-nodes)
The 2nd harmonic has wavelength exactly equal to L

Because f_n = n·f₁, the resonant frequencies are evenly spaced: the second harmonic is twice the first, the third is three times the first, and so on. A graph of frequency against harmonic number is therefore a straight line through the origin whose slope is the fundamental frequency f₁.

Off resonance

If the frequency is slightly wrong, reflections don't line up — the pattern blurs and shrinks instead of standing still.

Higher harmonic

More anti-nodes, shorter wavelength (λ = 2L/n), higher frequency (f = n·f₁).

More tension

Faster waves (v = √(T/μ)), so every resonant frequency rises.

QuantityRelationshipNotes
Wave speedv = fλ = √(T/μ)same for all harmonics on one string
Wavelength of harmonic nλ_n = 2L/n2nd harmonic: λ = L
Frequency of harmonic nf_n = n·v/(2L)f_n = n·f₁
Anti-nodesnhumps in the pattern
Nodes (incl. ends)n + 1points that stay still

Instructions — Running the Virtual Experiment

The Pulse tab lets you measure the wave speed by timing a single pulse; the Harmonics tab lets you drive the string and lock in standing-wave patterns. Record every reading in your lab report, with screenshots of each pattern.

Part A — Measuring Wave Speed (Pulse tab)
1
Open Simulation → Pulse. The string is fixed at the far end with damping off. Note the string length L shown on the ruler. Set the tension to Low for Part A.
2
Press Send pulse and use the on-screen timer to measure how long the pulse takes to travel from the wrench to the fixed end. Record the time and the length.
3
Calculate the wave speed v = length ÷ time, to three significant figures. Estimate the uncertainty from your reaction time with the stopwatch.
Part B — Resonance and Harmonics (Harmonics tab)
1
Open Harmonics. Slowly raise the frequency until the string forms a single large hump (one anti-node) — this is the first harmonic. The resonance indicator lights up when you are locked on.
2
Continue raising the frequency to find the second harmonic (two anti-nodes) and the third harmonic (three anti-nodes). For each, record the frequency and measure the wavelength (recall λ = 2L/n).
3
Verify v = fλ for each harmonic and compare with Part A. Then raise the tension to High and observe how the resonant frequencies change.

Simulation — Waves on a String

Standing Waves Virtual LabSend a pulse to measure the wave speed
pulse
String length 1.00 m · fixed far end · damping off.

Tension & pulse

Pulse timer
String length L1.00 m
TensionLow
Travel time— s
Wave speed v = L/t— m/s
Press “Send pulse” and read the travel time.
anti-node
node
Lock onto a resonant frequency to form a standing wave.

Drive the string

Standing wave
Driving frequency3.0 Hz
Wave speed v12.0 m/s
Resonance?no
Harmonic n
Anti-nodes
Wavelength λ = 2L/n— m
Raise the frequency slowly to find a harmonic.
Harmonic nAnti-nodesResonant f (Hz)Wavelength λ = 2L/n (m)v = fλ (m/s)
Lock onto each harmonic (or use the buttons) to fill this table.

Team Questions

Question 1. A pulse travels the 1.00 m string in 0.0833 s. What is the wave speed, to three significant figures? Use v = L/t. (Type just the number in m/s — e.g. 12.0)
Question 2. On a 1.00 m string, what is the wavelength of the second harmonic? Use λ = 2L/n. (Type just the number in metres)
Question 3. If the wave speed is 12.0 m/s on a 1.00 m string, what is the frequency of the first harmonic? Use f₁ = v/(2L). (Type just the number in Hz)
Question 4. For the same string, what is the frequency of the third harmonic? (Hint: f₃ = 3·f₁.) (Type just the number in Hz)
Question 5. Multiply the second-harmonic frequency (12.0 Hz) by its wavelength (1.00 m). What does this product equal, and how does it compare to the wave speed? (Type just the number in m/s)
Question 6. If you raise the tension to High, do you need a higher or lower frequency to reach the second harmonic? (Answer "higher" or "lower")
Question 7 — Challenge. Why does the string look messy and the pattern fail to stand still when you are slightly off the resonant frequency? (One key idea)

Example Lab Report

Sample report demonstrating the expected format and level of detail. Use as a guide for your own submission, and remember to include labelled screenshots of each standing-wave pattern.

Exploring Standing Waves and String Harmonics

Physics | Section: [Your Section] | Date: [Date]

Lab Members: [Names of all members present]

Purpose

To measure the speed of a wave on a string by timing a single pulse, to find the first three harmonics of the string fixed at both ends, to measure the frequency and wavelength of each harmonic, and to verify the relationship v = fλ. The experiment also examines how string tension affects the wave speed and the resonant frequencies.

Theory

A wave on a string travels at speed v = √(T/μ) and obeys v = fλ. For a string of length L fixed at both ends, standing waves occur only at resonant frequencies for which a whole number of half-wavelengths fits on the string, giving λ_n = 2L/n and f_n = n·v/(2L) = n·f₁. The n-th harmonic has n anti-nodes.

v = fλ = √(T/μ)
λ_n = 2L/n · f_n = n·v/(2L) = n·f₁ (L = 1.00 m)

Part A — Wave Speed (Low tension)

Measurement: pulse travel time t = 0.0833 s over length L = 1.00 m

Wave speed: v = L/t = 1.00 / 0.0833 = 12.0 m/s (3 s.f.)

Uncertainty: with a reaction-time uncertainty of about ±0.02 s in the stopwatch reading, v is uncertain by roughly ±3%.

Part B — Harmonics (Results Table, L = 1.00 m, Low tension)

Harmonic nAnti-nodesFrequency f (Hz)Wavelength λ = 2L/n (m)v = fλ (m/s)
116.002.0012.0
2212.01.0012.0
3318.00.66712.0

A graph of frequency against harmonic number was a straight line through the origin with slope f₁ = 6.00 Hz.

Discussion

The product fλ was 12.0 m/s for all three harmonics, matching the wave speed measured from the pulse in Part A and confirming v = fλ. The resonant frequencies were in the ratio 1 : 2 : 3, so frequency was directly proportional to harmonic number, with slope equal to the fundamental frequency. The second-harmonic wavelength equalled the string length, as expected from λ = 2L/n.

Slightly off a resonant frequency, the reflected and incoming waves no longer reinforced consistently, so the pattern blurred and shrank rather than standing still — only at the resonant frequencies do the reflections superimpose to give stable nodes and anti-nodes. When the tension was raised to High, the wave speed increased (v = √(T/μ)), so a higher frequency was needed to reach the same harmonic. Of the three measured quantities, time was the hardest to measure accurately because of reaction-time error with the stopwatch; frequency and length were comparatively easy to read.

Conclusion

The wave speed on the string was 12.0 m/s, consistent between the pulse method and the v = fλ check across all three harmonics. The harmonics followed f_n = n·f₁ and λ_n = 2L/n, and raising the tension raised the resonant frequencies, confirming v = √(T/μ).

Practice Questions

Show all work and include units. Assume a string fixed at both ends unless told otherwise.

Question 1
A 1.50 m string carries waves at 18.0 m/s. Find the frequency and wavelength of the first three harmonics.
Hint: λ_n = 2L/n and f_n = n·v/(2L).
Question 2
The third harmonic of a 2.00 m string has a frequency of 30.0 Hz. What is the wave speed on the string?
Hint: λ₃ = 2L/3, then v = f₃·λ₃ (or v = 2L·f₃/3).
Question 3
A pulse takes 0.125 s to travel a 1.00 m string. Compute the wave speed to three significant figures, then predict the first-harmonic frequency.
Hint: v = L/t; f₁ = v/(2L).
Question 4
Explain why a graph of resonant frequency versus harmonic number is a straight line through the origin, and state what its slope represents.
Hint: f_n = n·f₁, so frequency ∝ n; the slope is the fundamental frequency f₁.
Question 5
A guitar string is tightened so its tension quadruples. By what factor does the wave speed change, and by what factor do all the resonant frequencies change?
Hint: v = √(T/μ); quadrupling T doubles v, so every f_n doubles.
Question 6 — Challenge
A string of length 0.80 m and mass per unit length 0.0050 kg/m is under 20 N of tension. Find the wave speed and the first three harmonic frequencies.
Hint: v = √(T/μ) = √(20/0.0050); then f_n = n·v/(2L).