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Unit Conversions — Dimensional Analysis

Master unit conversions using the factor-label (dimensional analysis) method. Use the live converter, complete guided lab experiments, and test your knowledge in practice and quiz modes.

Theory — Dimensional Analysis

The factor-label method — the one technique that makes all unit conversions systematic and error-proof.

The Factor-Label Method

Every conversion is just multiplication by a fraction equal to 1. Since the numerator and denominator are equal quantities in different units, the value does not change — only the unit changes.

conversion factor = (desired unit) / (given unit)
given value × (desired unit / given unit) = answer in desired unit

Key rule: Put the unit you want to KEEP on top and the unit you want to CANCEL on the bottom.

Example: Convert 5 miles to kilometres
5 miles × (1.60934 km / 1 mile) = 8.047 km

Multi-Step Conversions

Chain multiple conversion factors in one line. Units cancel diagonally — the pattern extends as far as needed.

60 mi/hr × 1.60934 km1 mi × 1000 m1 km × 1 hr3600 s = 26.82 m/s

Write out every step and cancel units before multiplying. This prevents errors and shows your work clearly.

Temperature — Special Case

Temperature uses equations, not simple multiplication, because the scales have different zero points.

°C to K:   K = °C + 273.15
°F to °C: °C = (°F − 32) × 5/9
°C to °F: °F = (°C × 9/5) + 32
°F to K:   K = (°F − 32) × 5/9 + 273.15

Chemistry always uses Kelvin (K) for gas law calculations. Never use °C or °F in PV = nRT.

SI Prefixes

PrefixSymbolFactorExample
GigaG10⁹1 GHz = 10⁹ Hz
MegaM10⁶1 MJ = 10⁶ J
Kilok10³1 km = 1000 m
Decid10⁻¹1 dm = 0.1 m
Centic10⁻²1 cm = 0.01 m
Millim10⁻³1 mm = 0.001 m
Microμ10⁻⁶1 μm = 10⁻⁶ m
Nanon10⁻⁹1 nm = 10⁻⁹ m
Picop10⁻¹²1 pm = 10⁻¹² m

Key Conversion Factors Reference

📏 Length
1 in= 2.54 cm
1 ft= 0.3048 m
1 mile= 1.60934 km
1 m= 100 cm = 1000 mm
1 km= 1000 m
1 Å= 10⁻¹⁰ m
1 nm= 10⁻⁹ m
⚖ Mass
1 kg= 1000 g
1 lb= 453.592 g
1 oz= 28.3495 g
1 tonne= 1000 kg
1 amu= 1.66054×10⁻²⁷ kg
1 mg= 10⁻³ g
1 μg= 10⁻⁶ g
🧪 Volume
1 L= 1000 mL
1 mL= 1 cm³
1 gal (US)= 3.78541 L
1 fl oz= 29.5735 mL
1 qt= 0.946353 L
1 m³= 1000 L
1 dL= 100 mL
⚡ Energy
1 kJ= 1000 J
1 cal= 4.184 J
1 kcal= 4184 J
1 eV= 1.602×10⁻¹⁹ J
1 kWh= 3.6×10⁶ J
1 BTU= 1055.06 J
🌡 Pressure
1 atm= 101325 Pa
1 atm= 760 mmHg
1 atm= 760 torr
1 bar= 100000 Pa
1 psi= 6894.76 Pa
1 kPa= 1000 Pa
⚗ Chemistry
1 mol= 6.022×10²³ particles
1 M= 1 mol/L
R= 8.314 J/(mol·K)
R= 0.08206 L·atm/(mol·K)
1 nm= 10⁻⁹ m (wavelength)
1 g/mol= 1 amu/molecule

Live Converter

Select a category, enter a value, and see the full dimensional analysis working shown step by step.

Dimensional Analysis — Factor-Label Method
Select a category and enter a value to see the working.

Lab Experiments

Four structured experiments building from basic to multi-step conversions. Show all working using dimensional analysis.

1
Experiment 1 — Length and Distance Conversions
1
Convert each length. Write the full dimensional analysis in the working column. Use the Live Converter to check.
2
For each row: write the conversion factor used, show units cancelling, then give the final answer.
Given ValueConvert ToConversion Factor UsedYour AnswerCheck
5.00 inchescentimetres
100 metresfeet
26.2 mileskilometres
550 nmmetres
3.50 Ånanometres
2
Experiment 2 — Mass, Volume and Density
1
Convert each mass and volume. Remember density = mass/volume — units must be consistent before using this equation.
Given ValueConvert ToYour AnswerCheck
2.50 lbsgrams
355 mLlitres
1.50 gallonsmillilitres
0.789 g/mL (ethanol density)kg/m³
18.0 g/mol water, 18.0 mL/moldensity in g/mL
3
Experiment 3 — Temperature and Energy
1
Temperature uses equations not multiplication. Show the equation used and substitute the value.
2
For energy conversions use dimensional analysis as normal.
Given ValueConvert ToEquation/Factor UsedYour AnswerCheck
100 °C (boiling water)Kelvin
98.6 °F (body temperature)°C
−196 °C (liquid nitrogen)Kelvin
500 caloriesjoules
1 kilowatt-hourmegajoules
4
Experiment 4 — Multi-Step and Chemistry Conversions
1
These require multiple conversion factors chained together. Write each step showing unit cancellation.
2
For mole conversions: moles = mass / molar mass. Avogadro's number = 6.022 × 10²³.
GivenConvert ToSteps NeededYour AnswerCheck
60 miles/hourmetres/secondmi→km→m, hr→s
2.50 atmkPaatm→Pa→kPa
18.0 g of water (MW=18 g/mol)molesg ÷ g/mol
0.500 mol of NaClmoleculesmol × Avogadro
500 mmHgatmmmHg ÷ 760

Practice Problems

Work each problem fully before checking. Show your dimensional analysis working.

Example Lab Report

Sample report demonstrating the expected format and level of detail. Use as a guide for your own submission.

Unit Conversions: Dimensional Analysis

Physics 171  |  Section: [Your Section]  |  Date: [Date]
Lab Members: [Names of all members present]

Purpose

To master the factor-label (dimensional analysis) method for converting between units within the same physical category — length, mass, volume, temperature, pressure, energy, speed, and amount of substance — and to apply the method to multi-step conversions involving two or more conversion factors. The accuracy of each conversion is verified against accepted conversion factors.

Theory

Every unit conversion is a multiplication by a fraction equal to 1. The numerator and denominator of the fraction represent the same physical quantity expressed in two different units, so multiplying by this fraction changes the units without changing the value. The unit to be canceled is placed in the denominator; the desired unit is placed in the numerator:

given value × (desired unit / given unit) = answer in desired unit

For multi-step conversions, several such fractions are chained together in a single line. Units cancel diagonally down the chain until only the target unit remains. Temperature is a special case because the Celsius, Fahrenheit, and Kelvin scales do not share a common zero point — temperature uses equations rather than simple multiplication:

K = °C + 273.15     °C = (°F − 32) × 5/9

Percent error compared to an accepted value is calculated as:

% error = |experimental − accepted| / accepted × 100%

Calculations — Sample: 60 miles/hour to metres/second

Step 1 — Identify the conversion factors:
1 mile = 1609.34 m, 1 hour = 3600 s

Step 2 — Set up the dimensional analysis chain:
60 mi/hr × (1609.34 m / 1 mi) × (1 hr / 3600 s)

Step 3 — Cancel units:
mi cancels with mi, hr cancels with hr, leaving m/s ✓

Step 4 — Multiply:
(60 × 1609.34) / 3600 = 96 560.4 / 3600 = 26.82 m/s

Temperature example — Convert 98.6 °F to °C (body temperature):
°C = (98.6 − 32) × 5/9 = 66.6 × 5/9 = 37.0 °C ✓

Multi-step example — Convert 2.50 atm to kilopascals:
2.50 atm × (101 325 Pa / 1 atm) × (1 kPa / 1000 Pa) = 253.31 kPa

Results Table

CategoryGiven ValueTarget UnitAnswerAccepted Value% Error
Length 5.00 in cm 12.70 cm 12.70 cm 0.00%
Length 26.2 mi km 42.16 km 42.16 km 0.00%
Mass 2.50 lb g 1133.98 g 1133.98 g 0.00%
Volume 1.50 gal mL 5678.12 mL 5678.12 mL 0.00%
Temperature100 °C K 373.15 K 373.15 K 0.00%
Temperature98.6 °F °C 37.00 °C 37.00 °C 0.00%
Pressure 2.50 atm kPa 253.31 kPa 253.31 kPa 0.00%
Energy 500 cal J 2092.0 J 2092.0 J 0.00%
Speed 60 mph m/s 26.82 m/s 26.82 m/s 0.00%
Chemistry 0.500 mol molecules3.011 × 10²³3.011 × 10²³0.00%

Discussion

All conversions agreed with the accepted values to within the precision of the conversion factors used. The factor-label method was applied successfully to every category — length, mass, volume, pressure, energy, speed, and chemical amount — and the same method extended naturally to multi-step conversions such as mph to m/s, which required two factors chained together, and atm to kPa, which used Pa as an intermediate unit.

Temperature conversions were handled separately because the Celsius, Fahrenheit, and Kelvin scales have different zero points. The equation K = °C + 273.15 gives only an additive shift, while °C ↔ °F requires both a scale factor (5/9 or 9/5) and an offset (32). Using a simple multiplicative factor for temperature would give meaningless answers, which is why the factor-label method does not apply here.

The most common source of error in dimensional analysis is placing a conversion factor upside down — putting the unit to cancel in the numerator instead of the denominator. Writing every step out and visually checking that units cancel diagonally is the best way to prevent this error.

Conclusion

The experiment successfully demonstrated that dimensional analysis is a reliable, systematic method for converting between units. All ten representative conversions across seven categories produced answers that matched accepted values to the full precision of the conversion factors. The method scales naturally from one-step to multi-step conversions and handles chemistry calculations involving Avogadro's number with the same workflow. Temperature remains the only category that requires equation-based conversion rather than multiplicative factors.

Quiz Mode

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Q 1 of 10
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