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UV-Visible Spectroscopy

Ultraviolet-visible spectroscopy measures the absorption of UV (200-400 nm) and visible (400-700 nm) light by molecules. The absorbed light promotes valence electrons from bonding to antibonding orbitals (\u03c0\u2192\u03c0*, n\u2192\u03c0*, etc.). The wavelengths and intensities reveal the chromophores present (carbonyls, aromatic rings, conjugated systems, dyes), and Beer-Lambert\'s law connects absorbance to concentration for quantitative analysis. UV-Vis is one of the simplest, fastest, and most widely-used analytical techniques in chemistry, biology, and pharmaceutical research.

Theory — UV-Visible Spectroscopy

1. The basic UV-Vis experiment

A UV-Vis spectrophotometer passes monochromatic light through a sample (typically dissolved in a transparent solvent and held in a 1 cm-path cuvette) and measures how much light passes through compared to a blank. The absorbance A is computed as A = log₁₀(I₀/I), where I₀ is the incident intensity and I is the transmitted intensity. Modern instruments scan over a range (e.g., 200-800 nm) to give the full absorption spectrum.

2. Electronic transitions

UV-Vis absorption corresponds to electronic transitions: a valence electron is promoted from a filled orbital to an empty (or partially-filled) higher-energy orbital. The energy gap determines the wavelength absorbed (E = hc/λ). Common transitions in organic molecules:

TransitionEnergyTypical λ rangeExamples
σ \u2192 σ*Highest120-150 nm (vacuum UV)Saturated alkanes; not useful in routine UV-Vis
n \u2192 σ*High150-200 nmAlcohols, ethers, halides; usually below detection range
π \u2192 π*Variable (depends on conjugation)180-700 nmAlkenes (170-180), conjugated dienes (220-260), aromatics (250-280), polyenes (300-700)
n \u2192 π*Low (forbidden, weak)270-330 nmCarbonyls (acetone n\u2192\u03c0* at 280 nm, ε~15)
d \u2192 d (transition metals)Variable400-700 nmColoured transition metal complexes; KMnO\u2084 (525 nm), Cu²\u207A (810 nm)
Charge transferVariable200-700 nmMetal complexes; donor-acceptor pairs; very intense (ε > 10,000)

3. Chromophores and chromophore extension

A chromophore is a structural feature that absorbs UV-Vis light. Most chromophores in organic chemistry are based on π-bonded systems (alkenes, aromatics, carbonyls, azo, nitro) and the electrons promoted are typically in π or non-bonding (n) orbitals.

Conjugation extends and red-shifts λmax. When π-bonds are conjugated, the energy gap between the highest occupied (HOMO) and lowest unoccupied (LUMO) molecular orbitals decreases, so absorption moves to longer wavelengths. This is why β-carotene (11 conjugated C=C bonds) absorbs in the visible range (~450 nm, orange) while a single C=C absorbs in the deep UV (~170 nm, invisible to the eye). Conjugated polyenes are responsible for the colours of carotenoids, lycopene, retinal, and many natural and synthetic dyes.

Systemλmax (nm)Notes
Single C=C (ethylene)~170Vacuum UV; not seen in routine spectra
1,3-Butadiene (2 conjugated C=C)~217UV; typical conjugated diene
1,3,5-Hexatriene (3 conjugated C=C)~258UV; structured
β-Carotene (11 conjugated C=C)~450Visible; orange colour
Lycopene (11 conjugated)~470Visible; red colour
Benzene (aromatic, 3 conjugated π)~254 (with vibrational structure)UV; structured
Naphthalene~275Two fused aromatic rings
Anthracene~360Three fused aromatic rings; near-visible blue

4. The Beer-Lambert Law

Absorbance is linearly related to concentration and path length:

Beer-Lambert Law A = ε × c × l
where:
  A = absorbance (dimensionless; log₁₀ ratio)
  ε = molar absorptivity (L mol⁻¹ cm⁻¹)
  c = molar concentration (mol L⁻¹)
  l = path length (cm; typically 1.0)
For accurate quantitation, A should be in the range 0.2-1.0 (linear region). Above 1.0, dilute the sample. Below 0.2, concentrate or use a longer path length.

Molar absorptivity ε is a property of the molecule + the wavelength, not of the concentration. It quantifies how strongly a chromophore absorbs at a given λ. Strong chromophores (allowed transitions, intense colours) have ε = 10,000 to 100,000+. Weak chromophores (forbidden transitions, like n\u2192\u03c0* of carbonyls) have ε = 10-100. Knowing ε lets you calculate concentration from a measured absorbance.

5. Common chromophores and their typical λmax + ε values

Chromophoreλmax (nm)ε (M⁻¹ cm⁻¹)Transition
Saturated alkane (C-H)< 150--σ\u2192σ*
Alcohol/ether (-OH, -OR)~180~200n\u2192σ*
Single C=C alkene~170~10,000π\u2192π*
Acetone (n\u2192π*)~280~15n\u2192π* (carbonyl forbidden)
Acetone (π\u2192π*)~190~1000π\u2192π* (carbonyl, allowed)
Acrolein (CH\u2082=CH-CHO)~330 + 215~25 + 12,000n\u2192π* + π\u2192π*
Benzene~254~200π\u2192π* (Forbidden, structured)
Aniline (Ph-NH\u2082)~280~1500π\u2192π* with NH\u2082 lone pair
Methyl orange (azo dye)~465~25,000π\u2192π* extended; pH indicator
β-Carotene~450~140,000π\u2192π* extended polyene
KMnO\u2084 (permanganate)~525~2,500Charge transfer (LMCT)
Cu(H\u2082O)\u2086²\u207A~810~10d-d (forbidden, weak)

6. Solvent effects

Solvent affects λmax in two ways: (a) it must be transparent in the wavelength range of interest, (b) it can shift λmax via solvent-solute interactions. Solvent cutoff is the wavelength below which the solvent itself absorbs:

SolventUV cutoff (nm)Notes
Water190Best for very deep UV; excellent for charged or polar compounds
Methanol205Wide UV range; flammable; toxic
Ethanol205Similar to MeOH; less toxic
Acetonitrile190Best non-aqueous; good for all UV
Hexane / Cyclohexane200For non-polar compounds
Acetone330!NOT useful below 330 nm; absorbs strongly itself
Diethyl ether220Limited; flammable
Chloroform245Limited UV range; halogen absorption

Solvatochromism (solvent-induced shift): polar solvents red-shift π\u2192π* transitions (more polar excited state stabilised more by polar solvent) and blue-shift n\u2192π* transitions (lone pair H-bonded by polar solvent, lowering its energy and increasing the gap to π*).

7. Practical applications

Memorise these UV-Vis landmarks Single C=C: ~170 nm (vacuum UV)
Carbonyl n\u2192\u03c0*: ~280 nm, weak (ε ~15)
Carbonyl \u03c0\u2192\u03c0*: ~190 nm, strong (ε ~1000)
Benzene: ~254 nm, structured
Tryptophan / tyrosine: ~280 nm (protein quantitation)
DNA bases: ~260 nm
Conjugation extends: each new conjugated C=C adds ~30 nm to λmax
β-Carotene: ~450 nm (orange visible)
Methyl orange: ~465 nm (orange-red visible)
KMnO\u2084: ~525 nm (purple visible)
A λmax in the visible range (400-700 nm) means the compound is COLOURED. The colour you see is the COMPLEMENT of what is absorbed (e.g., absorbs ~450 nm blue light \u2192 you see orange-yellow).

8. Systematic UV-Vis analysis approach

  1. Identify the absorption maxima. Note the λmax values and approximate ε (from peak intensity).
  2. Match to chromophore type. λmax in UV (200-280)? Aromatic. λmax in near-UV (270-330)? Likely n\u2192\u03c0* (carbonyl). λmax in visible (400-700)? Conjugated or charge-transfer.
  3. For quantitation: Use Beer-Lambert at the chosen λ (use λmax for max sensitivity).
  4. For unknown structure: Combine with NMR (gives connectivity) and IR (gives functional groups). UV-Vis adds chromophore information.

Instructions

The Simulation has four parts. Complete in order.

1
Section I — Chromophore Library. 8 cases. For each: identify the wavelength region; identify the electronic transition; identify the chromophore type.
2
Section II — UV-Vis Spectrometer Bench. 6 unknown cuvettes. Click "Acquire Spectrum", view the absorption spectrum, identify the compound. Peak labels appear after you answer.
3
Section III — Spectrum Interpretation. 8 puzzles: Beer-Lambert quantitation, conjugation extension, solvent effects, identifying compounds from full UV-Vis data.
4
Section IV — SDS & Microscale. SDS for 4 UV-Vis materials (quartz cuvettes, common solvents, deuterium/tungsten lamps, Beer-Lambert standard prep) = 16 questions. Then 6 microscale sample-prep scenarios.
5
Prepare your lab notebook. Use the Example Report as your template.

Prerequisite: Familiarity with organic functional groups and the IR + Mass Spec + NMR labs. UV-Vis is the fourth and final lab in the spectroscopy quartet, completing the structural identification toolkit.

Simulation

Four interactive parts. Use the ↺ Reset Simulation button to clear all answers.

UV-Vis Workbench Section I — Chromophore Library

Eight chromophore-identification cases. For each: (a) wavelength region; (b) electronic transition; (c) chromophore type.

Score: 0 / 24

Six unknown cuvette samples. Click Acquire Spectrum, identify the compound from the UV-Vis spectrum. Peak labels appear after you answer.

Score: 0 / 6

Eight harder puzzles: Beer-Lambert quantitation, conjugation, solvent effects.

Score: 0 / 8

Round 1 — SDS interpretation

Four UV-Vis materials. Each has 4 questions.

SDS score: 0 / 16

Round 2 — Microscale sample prep

Six sample-prep scenarios.

Microscale score: 0 / 6

Team Questions

Discuss with your team before answering.

Question 1 — Beer-Lambert. Write the Beer-Lambert equation and identify each variable.
Question 2 — Conjugation. Why does β-carotene (11 conjugated C=C) absorb visible light while ethylene (1 C=C) does not?
Question 3 — Carbonyl transitions. Why is acetone\'s n\u2192\u03c0* transition (280 nm) so much weaker (ε ~15) than typical π\u2192\u03c0* transitions (ε ~10,000)?
Question 4 — Complementary colours. A solution looks yellow-orange to your eye. Approximately what wavelength does it absorb?
Question 5 — Cuvette material. Why are quartz cuvettes used for UV measurements rather than glass?
Question 6 — Solvent choice. A compound absorbs at λmax = 250 nm. Why is acetone NOT a suitable solvent?

Example Lab Notebook Entry

Use the format below as a template.

UV-Visible Spectroscopy — Lab Notebook Entry

Submitted by: [Student Name]

Course: Organic Chemistry I · Section: 201-A · Date: May 10, 2026

Objective

To learn the systematic interpretation of UV-Vis spectra: identifying the chromophore from λmax and ε; understanding how conjugation extends λmax; applying Beer-Lambert\'s law for quantitative concentration determination; recognising the limitations of UV-Vis (low specificity); and choosing appropriate solvents/cuvettes/lamps for accurate measurement.

Instrument bench results (Section II)

CuvetteCompoundλmax (nm)ε (M⁻¹ cm⁻¹)Visible colour
1Methanol (control)none above 205--colourless
2Acetone280 (n\u2192π*)~15colourless
3Benzene254 (\u03c0\u2192\u03c0*, structured)~200colourless
4β-Carotene450 (\u03c0\u2192\u03c0*, extended polyene)~140,000orange-yellow
5Methyl orange465 (azo \u03c0\u2192\u03c0*)~25,000orange-red
6KMnO\u2084 (aqueous)525 (charge transfer)~2,500purple

Discussion

UV-Vis spectroscopy probes the lowest-energy electronic transitions in a molecule. The basic principle: a photon of UV or visible light is absorbed when its energy exactly matches an electronic-transition gap (HOMO\u2192LUMO most often). The wavelength at which absorption is maximal (λmax) reflects the energy gap; the molar absorptivity (ε) reflects the transition probability (allowed vs forbidden, symmetric vs asymmetric).

For organic chemistry, the most useful transitions are π\u2192π* (typically ε = 10\u2074-10\u2075, intense) and n\u2192π* (typically ε = 10-100, weak because forbidden). Single C=C absorbs in the deep UV (~170 nm) and isn\'t seen in routine UV-Vis spectra; conjugated π-systems shift λmax progressively into the UV and visible. The classic series: 1,3-butadiene (217 nm) \u2192 1,3,5-hexatriene (258 nm) \u2192 longer polyenes (300+) \u2192 β-carotene\'s 11 conjugated C=C (450 nm). Each new conjugated C=C adds approximately 30 nm to λmax.

The instrument bench (Section II) demonstrates the entire range. Methanol shows no absorption above the solvent cutoff (~205 nm), serving as a clean baseline. Acetone shows a weak peak at 280 nm \u2014 this is the symmetry-forbidden n\u2192π* transition where a non-bonding lone pair on oxygen is promoted to the antibonding C=O π* orbital (low ε because the geometry change required for the transition is unfavourable). Benzene shows the structured \u03c0\u2192\u03c0* "B band" at 254 nm with vibrational fine structure (the multiple peaks come from coupling between the electronic transition and ring vibrations). Conjugated polyenes (β-carotene) show the extended \u03c0\u2192\u03c0* in the visible region. Azo dyes (methyl orange) show intense absorption from the electron-rich \u03c0-system around the N=N. Transition metal complexes (KMnO\u2084) show charge-transfer absorption (in this case ligand-to-metal: an electron from the O lone pair to the empty Mn 3d).

The Beer-Lambert law (A = εcl) is the basis for nearly all quantitative UV-Vis. For accurate quantitation, A should be in the linear range 0.2-1.0; outside this range, the response becomes non-linear (positive deviation from polychromatic light at high A; negative deviation from molecular interactions at very high concentration). Standard practice: prepare a calibration curve (5+ standards spanning the expected concentration range), measure A at λmax, plot A vs. c, fit a linear line, and use the slope (εl) to convert future A measurements to c.

Sample preparation matters. The cuvette must be transparent at the wavelength of interest \u2014 quartz (down to 200 nm) for UV; glass or polystyrene only for visible (above 320 nm). The solvent must not absorb at the analyte\'s λmax \u2014 acetone is unusable below 330 nm. Path length is typically 1.0 cm; for very dilute samples, longer (5-10 cm) cuvettes increase sensitivity. Concentration should be matched to give A in 0.2-1.0 range at λmax.

Compared to the other spectroscopic techniques in this quartet: UV-Vis tells us about chromophores and conjugation; IR identifies functional groups; NMR maps the carbon-hydrogen framework; MS determines molecular weight and fragmentation. UV-Vis is the LEAST specific (different compounds can have similar spectra), but it is FAST, INEXPENSIVE, and OFTEN USED FOR QUANTITATION (Beer-Lambert) where chromophore identity is already known.

Conclusion

UV-Vis spectroscopy is a workhorse analytical technique: simple, fast, sensitive, well-suited for quantitation. It complements the other spectroscopic methods (IR, NMR, MS) for full structural identification. Combined with Beer-Lambert quantitation, UV-Vis is widely used in pharmaceutical analysis, environmental monitoring, biochemistry, and chemistry teaching laboratories. The Spectroscopy quartet is now complete.

References

1. Pavia, D. L.; Lampman, G. M.; Kriz, G. S.; Vyvyan, J. R. Introduction to Spectroscopy, 5th ed., Cengage, 2015, Ch 2.
2. Silverstein, R. M.; Webster, F. X.; Kiemle, D. J. Spectrometric Identification of Organic Compounds, 8th ed., Wiley, 2014, Ch 7.
3. Skoog, D. A.; Holler, F. J.; Crouch, S. R. Principles of Instrumental Analysis, 7th ed., Cengage, 2017, Ch 13-14.
4. Perkampus, H.-H. UV-VIS Spectroscopy and Its Applications, Springer, 1992.

Practice Questions

Work through each before peeking at the hint.

Practice 1 — Beer-Lambert
A solution of an organic dye in a 1.0 cm path-length cuvette gives A = 0.45 at λmax = 480 nm. The molar absorptivity at 480 nm is ε = 22,500 M⁻¹ cm⁻¹. What is the concentration?
Hint: A = εcl. Solve: c = A/(εl) = 0.45/(22,500 \u00d7 1.0) = 2.0 \u00d7 10\u207B\u2075 M = 20 \u03BCM.
Practice 2 — Conjugation
A diene absorbs at 217 nm, a triene absorbs at 258 nm. Estimate λmax for a tetraene (4 conjugated C=C).
Hint: Each additional conjugated C=C bond adds ~30-40 nm. From triene 258 + 30 = 288, or 258 + 40 = 298. Real example: 1,3,5,7-octatetraene has λmax ~304 nm. Approximately 290-300 nm.
Practice 3 — Carbonyl λmax
Acetone\'s n\u2192π* is at 280 nm. For acrolein (CH\u2082=CH-CHO), where would the n\u2192π* be?
Hint: Acrolein has a conjugated C=C-C=O system. The conjugation lowers the LUMO (\u03c0*), so the n\u2192\u03c0* gap shrinks and λmax moves to LONGER wavelength. Acrolein\'s n\u2192\u03c0* is at ~330 nm, red-shifted from acetone\'s 280. Plus a strong \u03c0\u2192\u03c0* at 215 nm.
Practice 4 — Complementary colour
A solution appears red. What is the approximate λmax of the absorption?
Hint: Red light is what we see; the complementary colour absorbed is GREEN. Green light is at ~500-560 nm. So the absorption λmax is approximately 500-560 nm. Examples: KMnO\u2084 absorbs ~525 nm green and appears purple-red.
Practice 5 — Solvent cutoff
You want to measure a compound with λmax = 230 nm. Which of the following solvents are suitable: water, methanol, hexane, acetone, chloroform?
Hint: Solvent cutoffs: water (190), MeOH (205), hexane (200), acetone (330!), chloroform (245). To measure at 230 nm, the solvent must have a cutoff < 230. Water YES, MeOH YES (close), hexane YES, acetone NO (acetone absorbs strongly at 330 and below), chloroform NO (cutoff 245). Best choice: water or hexane.
Practice 6 — Cuvette choice
A measurement at 350 nm is being made. Can polystyrene cuvettes be used?
Hint: Polystyrene is transparent above ~320 nm. At 350 nm (visible region), polystyrene cuvettes are perfectly fine and are MUCH cheaper than quartz. For UV (below 320 nm), use quartz only.
Practice 7 — Protein quantitation
A protein has A = 0.32 at 280 nm in a 1.0 cm cuvette. The molar extinction coefficient is ε₂₈₀ = 16,500 M⁻¹ cm⁻¹. What is the concentration in mol/L?
Hint: c = A/(εl) = 0.32/(16,500 \u00d7 1.0) = 1.94 \u00d7 10\u207B\u2075 M \u2248 19 \u03BCM. Note: a protein\'s ε\u2082\u2088\u2080 mainly comes from tryptophan (5500 M\u207B\u00b9 cm\u207B\u00b9 per Trp) + tyrosine (1490) + cystine (125). The total ε is the sum across all aromatic residues.
Practice 8 — Solvent shift
A compound\'s n\u2192\u03c0* peak is at 320 nm in hexane and 305 nm in water. Why does it shift?
Hint: Polar protic solvent (water) hydrogen-bonds to the lone pair (n) on the heteroatom. This LOWERS the energy of the n orbital. The n\u2192\u03c0* GAP becomes LARGER, so λmax moves to SHORTER wavelength (blue shift). Hexane (non-polar) doesn\'t H-bond \u2014 the n orbital stays at higher energy, smaller gap, longer λ. The blue shift in water (320\u2192305) is a hallmark of n\u2192\u03c0* transitions and helps distinguish them from \u03c0\u2192\u03c0* (which red-shifts in polar solvents).
Practice 9 — A versus T
If you measure a UV absorbance value A = 2.5, why is this value untrustworthy and what should you do?
Hint: The Beer-Lambert linear range is roughly A = 0.2 to 1.0. At A = 2.5, only a TINY fraction of light reaches the detector (transmittance T = 10\u207B\u00b2\u00b7\u2075 = 0.3%); detector noise dominates the measurement. Solutions: (1) DILUTE the sample 10\u00d7 to bring A into 0.1-0.4 range; (2) use a SHORTER path length cuvette (e.g., 1 mm vs 10 mm); (3) measure at a DIFFERENT wavelength where ε is smaller. Modern instruments may extend the linear range to A = 2 or 3 with good optics, but 2.5 is at the edge.
Practice 10 — Combining techniques
An unknown shows: MS M⁺ = 122; IR strong C=O at 1685; \u00b9H NMR aromatic 5H + COOH 12 ppm; UV-Vis λmax = 230 + 273 nm. What is the compound, and what does each technique contribute?
Hint: M⁺ 122 + aromatic + C=O 1685 (slightly low for aromatic acid) + COOH NMR + UV \u03bb~273 (consistent with aromatic + carbonyl) = benzoic acid PhCOOH (MW 122). MS gives MW 122. IR confirms aromatic carbonyl (1685 lower than aliphatic acid 1715 due to conjugation). NMR confirms structure: 5H aromatic + 1H COOH. UV-Vis confirms aromatic conjugated with C=O (the 273 nm band is the para-substituted aromatic with conjugated EWG; the 230 nm is the K-band of the aromatic-carbonyl conjugation). Together: complete structural identification.